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pickupchik [31]
2 years ago
13

A researcher is conducting research on using technology in teaching. The researcher has two groups. The first group receives ins

truction via a PowerPoint presentation that is online. The second group attends a class and receives instruction from a teacher face to face. The researcher classifies the students based on when they volunteer for the study. The first 50 students who volunteer receive online instruction. The next 50 receive instruction by attending a class with a teacher. With respect to this study, we could identify that:
Mathematics
1 answer:
Troyanec [42]2 years ago
6 0

Answer:

This study is good because we have minimized sampling error.

Step-by-step explanation:

We are given that . The researcher has two groups.

The researcher classifies the students based on when they volunteer for the study.

The first 50 students who volunteer receive online instruction. The next 50 receive instruction by attending a class with a teacher.

A. This study is poor because the researcher did not use random sampling.

B. This study is poor because the researcher did used random sampling.

C. This study is good because we have minimized sampling error.

D. This study is good due to the equal sample size in each group.

Option C is true : This study is good because we have minimized sampling error.

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Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract
serg [7]

Answer:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Step-by-step explanation:

Given:

The equation to solve is given as:

x^2=-5x+8

Rearrange the given equation in standard form ax^2+bx +c =0, where, a,\ b,\ and\ c are constants.

Therefore, we add 5x-8 on both sides to get,

x^2+5x-8=0

Here, a=1,b=5,c=-8

The solution of the above equation is determined using the quadratic formula which is given as:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plug in a=1,b=5,c=-8 and solve for x.

x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Therefore, the solutions are:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

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