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melisa1 [442]
2 years ago
10

P and q are two numbers such that p > q

Mathematics
2 answers:
raketka [301]2 years ago
5 0

Answer:

3:2

Step-by-step explanation:

p-15: q-15

2:1

Using cross products

p-15 = 2(q-15)

p -15 =2q -30

Add 30 to each side

p +15 = 2q

p =2q - 15

30+p: q+30

5      :4

Using cross products

4(30+p) = 5(30+q)

120+4p = 150+5q

Subtract 120 from each side

4p = 30 +5q

Substitute the first equation in

4(2q -15) = 30 +5q

8q -60 = 30 +5q

Subtract 5q

3q -60 = 30

3q = 90

q = 30

Find p

p =2q - 15

p = 2*30 -15

p = 60-15

p = 45

ratio of p:q

45:30

Divide by 15

45/15 : 30/15

3:2

Ugo [173]2 years ago
5 0

Answer:

Step-by-step explanation:

p - 15 : q - 15 = 2 : 1

We know that when we use ratios, we're using fractions, so when we cross multiply:

1(p - 15) = 2(q - 15)

p - 15 = 2q - 30

p + 15 = 2q

p = 2q - 15     ....(1)

30 + p : q + 30 = 5 : 4

We know that when we use ratios, we're using fractions, so when we cross multiply:

4(30 + p) = 5(30 + q)

120 + 4p = 150 + 5q

4p = 30  + 5q     .....(2)

Substituting (1) in (2), we get:

= 4(2q - 15) = 30 + 5q

= 8q - 60 = 30 + 5q

3q - 60 = 30

3q = 90

= 30

Putting q = 30 in (1), we get:

p = 2 * 30 - 15

= 60 - 15

= 45

But we need to find the ratio of p : q (which is p/q)

So, 45 : 30

= 3 : 2

Hope this helps!

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Answer:

The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

Step-by-step explanation:

The data provided is as follows:

25 to 34              45 to 54

  1329                    2268

  1906                    1965

 2426                     1149

  1826                     1591

  1239                    1682

   1514                     1851

  1937                     1367

  1454                    2158

Compute the mean and standard deviation for the group "25 to 34" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01

Compute the <em>z</em>-score for the group "25 to 34" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1703.875}{394.01}=0.3734\approx 0.37

Compute the mean and standard deviation for the group "45 to 54" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39

Compute the <em>z</em>-score for the group "45 to 54" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1753.875}{383.39}=0.25333\approx 0.25

Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

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2 years ago
The difference between 907 sixteens and 856 twelves=
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(856/12) - (907/16) = 14.645833


So the difference is, 14.645833.
6 0
2 years ago
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The mass of a drop of water is about 0.025 of a gram. Which shows the mass written in scientific notation?
aleksklad [387]
2.5E-2 or 2.5x10^-2

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Use:

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World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of
Sunny_sXe [5.5K]

Answer:

a) W(t) = 371(1.168)^{t}

b) Wind capacity will pass 600 gigawatts during the year 2018

Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

(1.168)^{t} = 1.61725

We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

7 0
2 years ago
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