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uranmaximum [27]
2 years ago
3

Trapezoid JKLM with vertices J(-4,3),K (-2,7),L(2,7), and M(3,3) in the line y=1. Find the cord images of the reflected object.

Mathematics
1 answer:
Tju [1.3M]2 years ago
6 0

9514 1404 393

Answer:

  • J'(-4, -1)
  • K'(-2, -5)
  • L'(2, -5)
  • M'(3, -1)

Step-by-step explanation:

Reflection over the line y=1 is equivalent to the transformation ...

  (x, y) ⇒ (x, 2-y)

Then the transformed coordinates are ...

  J(-4, 3) ⇒ J'(-4, -1)

  K(-2, 7) ⇒ K'(-2, -5)

  L(2, 7) ⇒ L'(2, -5)

  M(3, 3) ⇒ M'(3, -1)

_____

You can do the arithmetic (as we have done above), or you can simply read the coordinates of the reflected points from the graph.

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After riding her bike for 20 miles. Angela got off and walked her bike the rest of the way at 5 miles per hour. If the total tri
mylen [45]

Answer:

She rode her bike 20 miles... I believe this may be a trick question.

Step-by-step explanation:

Let's break down this problem...

If she is going at a rate of 5 miles per hour while walking than the maximum she could have walked in 5 hours is 25 miles.

If Angela rode her bike for 20 miles, and the got off her bike and walked "<em>the rest of the way</em>" then she should have walked 50 miles. However as we already know her rate is 5 miles per hour while walking, and therefore could only have covered half that distance in 5 hours.

Is this a multiple choice question? Is there any misssing informaation?

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2 years ago
WILL BE BRANLIEST!!!
stiks02 [169]

Answer:

See explanation

Step-by-step explanation:

A. Solution set is in the attachment (dark green shading in the middle)

B. Yes, 2(5) + 3(1) ≤ 15; 13 is less than or equal to 15

5 + 1 > 3, 6 is greater than 3

C. (4, 2) means that he buys 4 sandwiches and 2 hot lunches

8 0
2 years ago
Read 2 more answers
Rahzel wants to determine how much gasoline he and his wife use in a month.He calculated that he used 78 1/3 gallons of gas last
attashe74 [19]
52. Rahzel wants to determine how much gasoline they had every month => He used 78 1/3 gallons of gas monthly => his wife used 41 3/8 gallons of gas last month How much is to total of gas that they both used. First let’s convert this fraction to decimal => 78 1/3 = 78.33 => 41 3/8 = 41.38 Now, let’s start adding. => 78.33 + 41.38 = 119.71 this is already rounded to the nearest hundredths.
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xeze [42]

Answer:

Step-by-step explanation:

6 0
2 years ago
Modern Vehicles Company came up with two different plans for the next financial year. Plan Y: Increase vehicle production by 5%
ladessa [460]

Answer: plan Y will produce more vehicles after 4 years.

Step-by-step explanation:

1) Plan Y: Increase vehicle production by 5% every year. It means that the rate of production is in geometric progression. The formula for determining the sum of n terms, Sn of a geometric sequence is expressed as

Sn = (ar^n - 1)/(r - 1)

Where

n represents the number of term(years) in the sequence.

a represents the first term(number of vehicles in the present year) in the sequence.

r represents the common ratio.

From the information given,

a = 10000

r = 1 + 5/100 = 1.05

n = 4 years

Therefore, the sum of the vehicles produced in the first 4 years, S4 is

S4 = (10000 × 1.05^(4) - 1)/1.05 - 1

S4 = (10000 × 0.21550625)/0.05

S4 = 2155.0625/0.05

S4 = 43101 vehicles

2) Plan Z: Increase production by 300 vehicles every year. It means that the rate of production is in geometric progression. The formula for determining the sum of n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

From the information given,

n = 4 years

a = 10000

d = 300

Therefore, the sum of the first 4 terms, S4 would be

S4 = 4/2[10000 × 2 + (4 - 1)300]

S4 = 2[20000 + (3)300]

S4 = 2 × 20900

S4 = 41800 vehicles

6 0
2 years ago
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