Question

The table shows experimental data of the magnitude of four forces exerted on a 2kg object as it slides across a horizontal surface. Which of the following could represent the magnitude of the net force that is exerted on the object? Select two answers.

Answer 1

Answer:

6N and 10N

Explanation:

The forces acting along the horizontal axis arw the horizontal force applied and the frictional force.

Frictional force is a force that opposes the horizontal force (moving force)

First we need to get the sum of force along the horizontal as shown

\sum Fx = Horizontal force - frictional force

\sum Fx = 8N - 2N

\sum Fx = 6N

Hence one of the magnitude of the net force exerted on the object is 6N

For the forces along the vertical component;

The forces are the weight, force of gravity(acting downward) and the normal force acting upward

Given

Weight = mass × acceleration die to gravity

Weight = 2×10 = 20N

Normal force = 10N

\sum Fy = (weight)-normal force

\sum Fy = (20)-10

\sum Fy = 20-10 = 10N

Hence the other net force acting on the object is 10N

The required options are 6N and 10N