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stiks02 [169]
2 years ago
5

Melanie buys 2 shells for $0.80. Rosi buys 3 shells for $1.20. Carlos buys 4 shells for $1.60. Use the graph to determine whethe

r there is a proportional relationship between the number of shells and their cost. If so, what does the constant of proportionality mean in this situation? Use the drop-down menus to show and explain your answer.

Mathematics
1 answer:
Agata [3.3K]2 years ago
4 0

Answer:

There's a proportion relationship between number of shell and their cost

Step-by-step explanation:

The graph is not given.

However, I've added the appropriate graph as an attachment.

From this, point....

I'll show that the cost and number of shells as given in the question are proportional.

Represent cost with y and number of shells with x

x = 2 when y = 0.8

x = 3 when y = 1.2

x = 4 when y = 1.6

Divide each value of y by x to get the constant of proportion (r).

r = y/x

r = 0.8/2 = 0.4

r = 1.2/3 = 0.4

r = 1.6/4 = 0.4

Notice that the values of r remain constant.

Hence, there's a proportion relationship between both

And what this rate represent is that:.the cost of shell changes at a constant rate when the number of shell is changes.

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Solve for x in the equation ? 2x^2 +3 x-7 =x^2 +5x +39
otez555 [7]

Answer:

1 ± √47

Step-by-step explanation:

Combine like terms in 2x^2 +3 x-7 =x^2 +5x +39:

2x^2 - x^2 = x^2 (first term);

3x - 5x = -2x (second term);

-7 - 39 = -46 (third term)

Then we have, all on the left side, x^2 - 2x - 46, which is a quadratic equation.  Here the coefficients are a = 1, b = -2 and c = -46.

Then the discriminant, b^2 - 4ac, is:

(-2)^2 - 4(1)(-46) = 4 + 184.

The roots are:

     -(-2) ±√188         2 ± √4√47

    ------------------- = -------------------

              2                         2

                             = 1 ± √47 (last of the answer choices)

=

x = ------------------

3 0
2 years ago
The Ignorance Survey: United Kingdom A survey was conducted in the United Kingdom, where respondents were asked if they had a un
lukranit [14]

Answer:

Here we have given two catogaries as degree holder and non degree holder.

So here we have to test the hypothesis that,

H0 : p1 = p2 Vs H1 : p1 not= p2

where p1 is population proportion of degree holder.

p2 is population proportion of non degree holder.

Assume alpha = level of significance = 5% = 0.05

The test is two tailed.

Here test statistic follows standard normal distribution.

The test statistic is,

Z = (p1^ - p2^) / SE

where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]

p1^ = x1/n1

p2^ = x2/n2

p^ = (x1+x2) / (n1+n2)

This we can done in TI_83 calculator.

steps :

STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER

Test statistic Z = 1.60

P-value = 0.1090

P-value > alpha

Fail to reject H0 or accept H0 at 5% level of significance.

Conclusion : There is not sufficient evidence to say that  the percent of correct answers is significantly different between degree holders and non-degree holders.

7 0
2 years ago
Jackson has 14 pet birds and rabbits. The total number of rabbits have 44 more legs than the total number of birds. How many pet
Tcecarenko [31]
I am unsure what you are talking about please improve your question next time please.
8 0
2 years ago
A survey of 225 students showed the mean number of hours spent studying per week was 20.6 and the standard deviations was 2.7
LekaFEV [45]

Answer:

The margin of error is approximately 0.3

Step-by-step explanation:

The following information has been provided;

The sample size, n =225 students

The sample mean number of hours spent studying per week = 20.6

The standard deviation = 2.7

The question requires us to determine the margin of error that would be associated with a 90% confidence level. In constructing confidence intervals of the population mean, the margin of error is defined as;

The product of the associated z-score and the standard error of the sample mean. The standard error of the sample mean is calculated as;

\frac{sigma}{\sqrt{n} }

where sigma is the standard deviation and n the sample size. The z-score associated with a 90% confidence level, from the given table, is 1.645.

The margin of error is thus;

1.645*\frac{2.7}{\sqrt{225}}=0.2961

Therefore, the margin of error is approximately 0.3

5 0
2 years ago
Read 2 more answers
Maria and Edwin have $23.00 each to spend at a book fair, where all students receive a 25% discount. They both want to purchase
Andreyy89
Maria : 26.50 - 0.25(26.50) = 26.50 - 6.625 = 19.88
            19.87 + 0.10(19.87) = 19.87 + 1.99 = 21.86

Edwin : 0.75(26.50) = 19.88
             1.10(19.88) = 21.86

and if they each have $ 23, then yes, they both ave enough money to buy the book. They both were correct in their calculations. Because taking 25% off, is the same as paying 75%.....and taking the discount price and subtracting 10% from that, is the same as multiplying by 110%. So they basically worked the same problem, just in a little different way...and they both ended up with the same answer


4 0
2 years ago
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