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2 years ago

how many minutes will it take the school bus to complete the 52-km trip back to the school at an average speed of 1.0 km/min?

Mathematics

2 answers:

goldfiish [28.3K]2 years ago

7 0

Answer: It will take 52min to complete the 52-km trip back to the school.

My name is Ann [436]2 years ago

4 0

Answer:

52 min

Step-by-step explanation:

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Suppose Kay inherits $250,000, which she invest today at a rate of return of 9% compounded annually. How much will Kay's investm

Nikolay [14]

Answer:

D.$2,155,770,17

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well

laiz [17]

Answer:

The value is $P(A) = 0.133617$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 7.5$

The standard deviation is $\sigma = 0.2$

The safest water level is between 7.2 and 7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

$P(A) = 1 - P(7.2 \le X \le 7.8 )$

Here

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } < \frac{X - \mu }{ \sigma }$

Generally $\frac{X - \mu }{ \sigma } = Z (The \ standardized \ value \ of X )$

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z$

$P(7.2 < X < 7.8 ) = P(-1.5 < Z$

=> $P(7.2 < X < 7.8 ) = P(Z < 1.5) - P( Z < - 1.5)$

From the z-table the probability of (Z < -1.5) and ( Z <1.5) are

$P(Z < 1.5) = 0.93319$

and

$P(Z < -1.5) = 0.066807$

$P(7.2 < X < 7.8 ) =0.93319 - 0.066807$

$P(7.2 < X < 7.8 ) =0.0866383$

$P(A) = 1 - 0.0866383$

=> $P(A) = 0.133617$

5 0

2 years ago

Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

4 0

2 years ago

Leah borrows £10,000 over 5 years at a simple interest rate of 15%.

Fynjy0 [20]

Answer:

She will pay $7,500 interest over the 5 years

She will have to pay back $17,500 in total

Step-by-step explanation:

Let us revise the rule of the simple interest

I = Prt and A = P(1 + rt) , where:

A = Total Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

r = Rate of Interest per year in decimal

t = Time Period involved in months or years

∵ Leah borrows £10,000 over 5 years at a simple interest rate of 15%.

∴ P = 10,000

∴ t = 5

∴ r = 15% = $\frac{15}{100}$ = 0.15

→ Substitute them in the first rule to find the interest

∵ I = 10,000(0.15)(5)

∴ I = 7,500

∴ She will pay $7,500 interest over the 5 years

→ Let us find A

∵ A = 10,000(1 + 0.15×5)

∴ A = 17,500

∴ She will have to pay back $17,500 in total

5 0

2 years ago

a salon owner noted what types of services its clients requested last week. Here are the results. 5% dye only, 30% haircut and d

soldi70 [24.7K]

Answer:

2/3

Step-by-step explanation:

So we have 10%+5%=15% of clients under the condition "permanent", and we can find the probability that a client in that group requested a haircut:

P(haircut | permanent)=10%/15%=2/3

3 0

2 years ago