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AVprozaik [17]
2 years ago
6

Suppose that Smartphone A has 256 MB RAM and 32 GB R OM, and the resolution of its camera is 8 MP; Smart- phone B has 288 MB RAM

and 64 GB R OM, and the resolution of its camera is 4 MP; and Smartphone C has 128 MB RAM and 32 GB R OM, and the resolution of its camera is 5 M P . Determine the truth v alue of each of these propositions. a) Smartphone B has the most RAM of these three smart- phones. b) Smartphone C has more R O M o r a higher resolution camera than Smartphone B. c) Smartphone B has more RAM, more R OM, and a higher resolution camera than Smartphone A. d) If Smartphone B has more RAM and more R O M than Smartphone C, then it also has a higher resolution camera. e) Smartphone A has more RAM than Smartphone B i f and only if Smartphone B has more RAM than Smart- phone A.
Mathematics
1 answer:
Sonbull [250]2 years ago
7 0

Answer:

A.) TRUE

B.) TRUE

C.) FALSE

D.) FALSE

E.) FALSE

Step-by-step explanation:

Given that :

SMARTPHONE A:

RAM : 256 MB

ROM : 32 GB

CAMERA RESOLUTION : 8 MP

SMARTPHONE B:

RAM : 288 MB

ROM : 64 GB

CAMERA RESOLUTION : 4 MP

SMARTPHONE C:

RAM : 128 MB

ROM : 32 GB

CAMERA RESOLUTION : 5 MP

Determine the truth value of each of these propositions.

A) Smartphone B has the most RAM of these three smart- phones.

TRUE ; 288 > (256 and 128)

B) Smartphone C has more R O M o r a higher resolution camera than Smartphone B.

C ROM > B ROM = FALSE

C CAMERA RESOLUTION > B camera resolution = TRUE

FALSE or TRUE = TRUE

C.) Smartphone B has more RAM, more R OM, and a higher resolution camera than Smartphone A.

RAM = TRUE ; ROM = TRUE ; CAMERA RESOLUTION = FALSE

TRUE and TRUE and FALSE = FALSE

d) If Smartphone B has more RAM and more R O M than Smartphone C, then it also has a higher resolution camera.

CAMERA RESOLUTION ON SMARTPHONE B IS LESS, HENCE, STATEMENT = FALSE

e) Smartphone A has more RAM than Smartphone B i f and only if Smartphone B has more RAM than Smart- phone A.

1st statement = FALSE

2nd condition = TRUE

FALSE and TRUE

= FALSE

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Caleb has 20 more books than Danica. If Caleb gives Danica half of his books, Danica will have 4 more books than Caleb. How many
wariber [46]

Answer:

Option E: 24.

Step-by-step explanation:

When Caleb (C) has 20 more books than Danica (D), we have:

C = 20 + D   (1)

Now, when Caleb gives Danica half of his books:

C' = C - \frac{C}{2}   (2)

Danica will have 4 more books than Caleb, so:

D' = D + \frac{C}{2}     (3)    

Also we have that:

D' = C' + 4   (4)  

By entering equation (2) and equation (3) into equation (4) we have:

D + \frac{C}{2} = C - \frac{C}{2} + 4   (5)

From (1) we have:

D = C - 20   (6)

By entering (6) into (5):

C - 20 + \frac{C}{2} = C - \frac{C}{2} + 4

C = 24

And, from (6):

D = C - 20 = 24 - 20 = 4  

Therefore, the correct option is E, Caleb had to start with 24 books.

I hope it helps you!          

3 0
2 years ago
What steps would you take to determine if these figures are similar? Check all that apply. Use a scale factor of 2. Multiply the
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Answer:

Well I took it"s Reflect the intermediate image.  and Multiply the vertices of polygon ABCD by One-half.

Step-by-step explanation:

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The arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

<em><u>Explanation</u></em>

The given formula is:   s=V_{0}t-16t^2

If the initial velocity is 96 ft/s , that means  V_{0}=96

For finding the time the arrow takes to reach a height of 48 ft, we will plug s= 48 into the above formula. So......

48=96t-16t^2\\ \\ 16t^2-96t+48=0\\ \\ 16(t^2-6t+3)=0\\ \\ t^2-6t+3=0\\ \\ t^2-6t =-3\\ \\ t^2-6t+9=-3+9\\ \\ (t-3)^2 = 6\\ \\ t-3= \pm \sqrt{6} \\ \\ t=3\pm \sqrt{6}\\ \\ t = 5.45 , 0.55

So, the arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

7 0
2 years ago
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The theoretical probability of an event occurring is Two-fifths. Which best describes the experimental probability associated wi
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Answer:

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B = hourly rate for babysitting and w = hourly rate for working at water park

3b + 10w = 109...multiply by -8
8b + 12w = 177...multiply by 3
----------------------
-24b - 80w = - 872 (result of multiplying by -8)
24b + 36w = 531 (result of multiplying by 3)
---------------------add
- 44w = - 341
w = -341/-44
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b = 31.50/3
b = 10.50 <== hourly rate for babysitting
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