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Travka [436]
2 years ago
11

Sea arches and sea stacks provide evidence of weathering and erosion. In three to five sentences, explain the roles weathering a

nd erosion play in creating these landforms.(4 points)
Chemistry
1 answer:
Montano1993 [528]2 years ago
4 0

Answer:

?

Explanation:

You might be interested in
When aqueous solutions of NH4OH(aq) and CuCl2(aq) are mixed, the products are NH4Cl(aq) and Cu(OH)2(s). What is the net ionic eq
Ilia_Sergeevich [38]

Answer:

2OH^-(aq) + Cu^2+(aq) -----> Cu(OH)2(s)

Explanation:

The net ionic equation usually shows the main ionic reaction that goes in the system. The other ions that do not participate in this net ionic equation are called spectator ions. Spectator ions do not participate in the main reaction occurring in the system.

The net ionic equation quite often result in the formation of a solid precipitate in the system such as Cu(OH)2.

The net ionic equation for this reaction is;

2OH^-(aq) + Cu^2+(aq) -----> Cu(OH)2(s)

5 0
2 years ago
The standard curve was made by spectrophotographic analysis of equilibrated iron(III) thiocyanate solutions of known concentrati
posledela

Answer:

Molar concentration of the Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.

Explanation:

When you make a calibration curve in a spectrophotographic analysis you are applying the Lambert-Beer law that states the concentration of a compound is directely proportional to its absorbance:

A = E*l*C

<em>Where A is absorbance, E is molar absorption coefficient, l is optical path length and C is molar concentration</em>

<em />

Using the equation of the line you obtain:

y = 4541.6X + 0.0461

<em>Where Y is absorbance and X is concentration -We will assume concentration is given in molarity-</em>

As absorbance of the unknown is 0.410:

0.410 = 4541.6X + 0.0461

X = 8.01x10⁻⁵M

<h3>Molar concentration of the Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.</h3>

<em />

6 0
2 years ago
Micky Mo is a 64-year-old male admitted to the emergency room for asthma. His laboratory results are as follows: pH 7.31, pCO2 h
Salsk061 [2.6K]

Answer:

Micky Mo is suffering from respiratory acidosis.

Explanation:

The pCO2 level in micky"s body is higher than normal it means the excess amount of  CO2 will reacts with water to generate carbonic acid(H2CO3).

  On the other hand according to the question total HCO3- also higher than normal.As a result the excess HCO3- will react with proton to form carbonic acid which is in turn dissociate to generate CO2 and H2O to maintain normal acid base homeostasis.

 From that point of view it can be said Micky Mo is suffering from respiratory acidosis.

5 0
2 years ago
The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when t
igomit [66]

Answer:

P_2=20atm

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

\frac{P_1}{T_1}= \frac{P_2}{T_2}

Thus, we solve for the final pressure P2 to obtain it as shown below:

P_2=\frac{P_1T_2}{T_1}=\frac{10atm*20K}{10K} \\\\P_2=20atm

Hence, we notice that the temperature doubles as well as the pressure.

Best regards.

3 0
2 years ago
Most Bic lighters hold 5.0ml of liquified butane (density = 0.60 g/ml). Calculate the minimum size container you would need to "
Hatshy [7]

Answer:

Volume of container = 0.0012 m³ or 1.2 L or 1200 ml

Explanation:

Volume of butane = 5.0 ml

density = 0.60 g/ml

Room temperature (T) = 293.15 K

Normal pressure (P) = 1 atm = 101,325 pa

Ideal gas constant (R) = 8.3145 J/mole.K)

volume of container V = ?

Solution

To find out the volume of container we use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

First we find out number of moles

<em>As Mass = density × volume</em>

mass of butane = 0.60 g/ml ×5.0 ml

mass of butane = 3 g

now find out number of moles (n)

n = mass / molar mass

n = 3 g / 58.12 g/mol

n = 0.05 mol

Now put all values in ideal gas equation

<em>PV = nRt</em>

<em>V = nRT/P</em>

V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa

V = 121.87 ÷ 101,325 pa

V = 0.0012 m³ OR 1.2 L OR 1200 ml

8 0
2 years ago
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