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Nesterboy [21]
2 years ago
4

Consider the function f(t) = StartRoot 3 t minus 9 EndRoot. You cannot take the square root of a negative number, so 3t – 9 must

be zero.
Mathematics
2 answers:
Anna35 [415]2 years ago
5 0

Answer:

Greater than or equal to

Step-by-step explanation:

Monica [59]2 years ago
5 0

Answer:

Greater than or equal to,    3t-9>0, Domain T> 3

Step-by-step explanation:

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Mei and Anju are sitting next to each other on different horses on a carousel. Mei's horse is 3 meters from the center of the
SOVA2 [1]

Answer:

2\pi \approx 6.28\ meters

Step-by-step explanation:

Mei's horse is 3 meters from the center of the carousel. After one rotation, Mei travelled

l_M=2\pi r=2\pi \cdot 3=6\pi\ meters

Anju's horse is 2 meters from the center. After one rotation, Mei travelled

l_A=2\pi r=2\pi \cdot 2=4\pi\ meters

The difference in their travelled distances is

l_M-l_A=6\pi -4\pi =2\pi \approx 6.28\ meters

5 0
2 years ago
Read 2 more answers
4. What can you infer about tax law in a state such<br> as Indiana, Connecticut, or Michigan?
iragen [17]

Answer:

Y’all cpensive

Step-by-step explanation:o think

5 0
2 years ago
Solve the inequality. c – 5 ≤ 6
Vilka [71]
Hello There!

Follow through:
c - 5\leq 6
Add 5 to both sides:
c - 5 + 5 ≤ 6 + 5
Simplify:
c ≤ 11

C is smaller than or equal to 11.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
3 0
2 years ago
Read 2 more answers
One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples
JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± t_{n_1+n_2-2;1-\alpha /2} * Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11

t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708

[(82.3-81.2) ± 1.708* (6.11*\sqrt{\frac{1}{15}+\frac{1}{12}  }]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0
2 years ago
Which polynomials are prime? Check all that apply. 2x2+ 7x + 1 5x2 – 10x + 5 3x2 + 8 4x2 – 25 x2 + 36
aleksley [76]
The correct answer would be 2x2+ 7x + 1, 3x2 + 8    and x2 + 36. These polynomials cannot be reduced to a lower degree where the factors are integers so they should be prime. The factors are as follows:

<span>2x2+ 7x + 1             -0.1492189406 and -3.350781059
5x2 – 10x + 5         1 and 1
3x2 + 8                     1.632993162i and - </span>1.632993162i<span>
4x2 – 25                  5/2 and -5/2
x2 + 36                    6i and -6i</span>
6 0
2 years ago
Read 3 more answers
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