Answer:
(e) the mean number of siblings for a large number of students has a distribution that is close to Normal.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
By the Central Limit Theorem
The sampling distributions with a large number of students(at least 30) will be approximately normal, so the correct answer is given by option e.
Answer:
Elliot has to wait 11 months before he has enough cars
Step-by-step explanation:
Elliot has 4 display cases with each case being able to hold 15 cars. Thus we know
total # of cars Elliot can place in his display case = 4 * 15 = 60 cars
From this, we can figure out how many more cars Elliot needs by subtracting the amount of cars he already has
# of cars Elliot needs = 60 - 28 = 32 cars
Now to find the number of months Elliot needs, we divide by how many he can buy each month
# of months Elliot needs to save up for = 32 / 3 = 10 2/3
Assuming Elliot does not get his allowance until the end of the month, we will have to round the number of months up to the nearest integer, 11
Answer:7
Step-by-step explanation:
This can be solved by Venn-diagram
Given there are total 5 students who want french and Latin
also 3 among them want Spanish,french & Latin
i.e. only 2 students wants both french and Latin only.
Also Student who want only Latin is 5
Thus Student who wants Latin and Spanish both only is 11-5-3-2=1
Students who want only Spanish is 8 Thus students who wants Spanish and French is 4
Similarly Students who wants Only French is 16-4-3-2=7
Answer:
n=2
Step-by-step explanation:
2000 pounds = 1 ton 600000 pounds = X tons Hence X tons = (600000 x 1) ÷ 2000 = 300 tons 3 x 10ⁿ = 300 Hence 3 x 10ⁿ = 3 x 10² Hence n= 2
To find cost per ounce divide the total price by the total ounces.
1.4 / 3.5
$ 0.40 per ounce
