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2 years ago

Which polynomials are prime? Check all that apply. 2x2+ 7x + 1 5x2 – 10x + 5 3x2 + 8 4x2 – 25 x2 + 36

Mathematics

2 answers:

aleksley [76]2 years ago

6 0

The correct answer would be 2x2+ 7x + 1, 3x2 + 8 and x2 + 36. These polynomials cannot be reduced to a lower degree where the factors are integers so they should be prime. The factors are as follows:

<span>2x2+ 7x + 1 -0.1492189406 and -3.350781059
5x2 – 10x + 5 1 and 1
3x2 + 8 1.632993162i and - </span>1.632993162i<span>
4x2 – 25 5/2 and -5/2
x2 + 36 6i and -6i</span>

Hoochie [10]2 years ago

4 0

Answer:

1:2x2+ 7x + 1

3:3x2 + 8

5:x2 + 36

Step-by-step explanation:

Hope this helps :)

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Zarrin [17]

Answer:

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Step-by-step explanation:

The area of the triangle is given by ...

A = (1/2)bh

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2 years ago

Six teachers and 12 students volunteer for a committee to discuss extra-curricular activities. How many committees of 5 people c

Alex17521 [72]

Answer:

a) $X=3300$

b) $Y=7770$

Step-by-step explanation:

From the question we are told that:

Number Teachers $T=6$

Number Student $S=12$

Number in committee $n=5$

a) Generally the equation for exactly 3 students on the committee is mathematically given by

$X=^{S}C_3*^{T}C_3$

$X=^{12}C_3*^{6}C_3$

$X=3300$

b) Generally the equation for at least one teacher and at least one student on the committee is mathematically given by

Total Ways-(no of ways of selection no teacher or student)

Where total Ways

$T=^{(6+12)}C_5$

$T=8568$

Therefore

$Y=8568-^{6}C_0*^{12}C_5+^{12}C_0*^{6}C_5$

$Y=8568-798$

$Y=7770$

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1 year ago

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Step-by-step explanation:

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1 year ago

Peter paid $79.80 for renting a tricycle for 6 hours. What was the rate per hour for renting the tricycle? (Input only numeric v

defon

Answer:

13.30

Step-by-step explanation:

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2 years ago

Read 2 more answers

A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit

viva [34]

Answer: D) $\$50\pm\$11.08$

Step-by-step explanation:

As per given , we have

Sample size : n= 15

sample mean : $\overline{x}=\$50.50$

Sample standard deviation: s= $20

Since population standard deviation is unknown , so we use t-test.

Significance level for 95% confidence : $\alpha=1-0.95=0.05$

Critical t-value : $t_{n-1, \alpha/2}=t_{014,0.025}=2.145$ [Using students' t-value table]

Required 95% Confidence interval :-

$\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08$

Hence, the required 95% confidence interval for the mean amount its credit card customers spent on their first visit to the chain's new store in the mall assuming that the amount spent follows a normal distribution.:

$\$50\pm\$11.08$

5 0

2 years ago