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antoniya [11.8K]

2 years ago

5

Five cards are labeled 1 to 5 face down on the table and then mixed up. What is the likelihood that I will draw an even-numbered

card?

2 answers:

marshall27 [118]2 years ago

7 0

It would be a 2/5 chance that youll pull and even card out.

Kaylis [27]2 years ago

4 0

First you do the even number up to five 1,2,3,4,5, the even numbers are 2 and 4
so you have a 2 out of five chance to get a even number.

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The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. I

Lostsunrise [7]

Answer:

The option which is:

On a coordinate plane, a parabola opens up. It goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10).

Step-by-step explanation:

At first we should know the rules of translation

1) {f(x) + a} is f(x) shifted up (a) units

2) {f(x) – a} is f(x) shifted down (a) units

3) {f(x + a)} is f(x) shifted left (a) units.

4) {f(x – a)} is f(x) shifted right (a) units.

Given:

f(x) = x²

g(x) = (x-5)² + 1

By comparing [ the translation from f(x) to g(x) ] with the rules of translation

We can deduce that g(x) is the image of f(x) by translation 5 units right and 1 unit up ( rules 1 and 4)

See the attached figure which represent the graph of f(x) and g(x)

As shown g(x) goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10)

3 0

2 years ago

Read 2 more answers

Twenty-nine percent of americans say they are confident that passenger trips to the moon will occur in their lifetime. You rando

CaHeK987 [17]

Answer:

the probability that less than 33% of the people sampled will answer yes to the question =0.5676

Step-by-step explanation:

8 0

2 years ago

"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the

Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

Expected observed Diff

x p(x) p(x)*1000

0 0.002 2

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144

5 0.189 189

6 0.238 238

7 0.178 178

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.

4 0

2 years ago

829.9 to the nearest whole number

anzhelika [568]

when rounding numbers: if it's four or less, you round down. if it's five or more, you round up. 9 is bigger than 4, so the nearest whole number is 830.

7 0

2 years ago

Read 2 more answers

Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin

tekilochka [14]

Answer:

1

$p(b) = \frac{1}{6}$

2

$p(k) = \frac{1}{3}$

3

$P(a) = \frac{1}{3}$

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

$p(b) = \frac{N}{n}$

$p(b) = \frac{6}{36}$

$p(b) = \frac{1}{6}$

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

$p(k) = \frac{2}{6}$

$p(k) = \frac{1}{3}$

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

$P(a) = \frac{W}{L}$

=> $P(a) = \frac{10}{30}$

=> $P(a) = \frac{1}{3}$

3 0

2 years ago