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Zielflug [23.3K]
2 years ago
12

Write a Python3 program to check if 3 user entered points on the coordinate plane creates a triangle or not. Your program needs

to repeat until the user decides to quit, and needs to deal with invalid inputs.
Computers and Technology
1 answer:
natulia [17]2 years ago
4 0

Answer:

tryagain = "Y"

while tryagain.upper() == "Y":

    x1 = int(input("x1: "))

    y1 = int(input("y1: "))

    x2 = int(input("x2: "))

    y2 = int(input("y2: "))

    x3 = int(input("x3: "))

    y3 = int(input("y3: "))

    area = abs(x1 *(y2 - y3) + x2 * (y1 - y3) + x3 * (y1 - y2))

    if area > 0:

         print("Inputs form a triangle")

    else:

         print("Inputs do not form a triangle")

    tryagain = input("Press Y/y to try again: ")

Explanation:

To do this we simply calculate the area of the triangle given that inputs are on plane coordinates i.e. (x,y).

If the area is greater than 0, then it's a triangle

If otherwise, then it's not a triangle.

This line initializes iterating variable tryagain to Y

tryagain = "Y"

while tryagain.upper() == "Y":

The following lines get the coordinates of the triangle

    x1 = int(input("x1: "))

    y1 = int(input("y1: "))

    x2 = int(input("x2: "))

    y2 = int(input("y2: "))

    x3 = int(input("x3: "))

    y3 = int(input("y3: "))

This calculates the area

    area = abs(x1 *(y2 - y3) + x2 * (y1 - y3) + x3 * (y1 - y2))

This checks for the condition stated above.

    if area > 0:

         print("Inputs form a triangle") This is printed, if true

    else:

         print("Inputs do not form a triangle") This is printed, if otherwise

    tryagain = input("Press Y/y to try again: ") This prompts the user to try again with another set of inputs

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Answer:

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Explanation:

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2 years ago
A computer’s memory is composed of 8K words of 32 bits each. How many bits are required for memory addressing if the smallest ad
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Answer:

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b. txRt  - A bad variable name because while short and simple, it is too hard to understand what the variable represents.

c. t  - A very bad variable name if you plan on using the variable often. Far too short and you will forget what it represents and is needed for.

d. stateSalesTaxRateValue  - A bad variable name because it is just too wordy. Cutting it down to A's variable name is much more reasonable

e. state tax rate  - A bad variable name and probably invalid because it has spaces in the name.

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7 0
2 years ago
Complete the function to replace any period by an exclamation point. Ex: "Hello. I'm Miley. Nice to meet you." becomes:
vodomira [7]

Answer:

Here is the complete function:

void MakeSentenceExcited(char* sentenceText) {  // function that takes the text as parameter and replaces any period by an exclamation point in that text

int size = strlen(sentenceText);  //returns the length of sentenceText string and assigns it to size variable

char * ptr;  // character type pointer ptr

ptr = sentenceText;  // ptr points to the sentenceText string

for (int i=0; i<size; i++){  //iterates through the sentenceText string using i as an index

    if (sentenceText[i]=='.'){  // if the character at i-th index of sentenceText is a period

        sentenceText[i]='!'; } } } //places exclamation mark when it finds a period at i-th index of sentenceText

Explanation:

The program works as follows:

Suppose we have the string:

sentenceText = "Hello. I'm Miley. Nice to meet you."

The MakeSentenceExcited method takes this sentenceText as parameter

int size = strlen(sentenceText) this returns the length of sentenceText

The size of sentenceText is 35 as this string contains 35 characters

size =  35

Then a pointer ptr is declared which is set to point to sentenceText

for (int i=0; i<size; i++) loop works as follows:    

1st iteration:

i=0

i<size is true because i=0 and size = 35 so 0<35

So the body of loop executes:

 if (sentenceText[i]=='.') statement checks :

if (sentenceText[0]=='.')

The first element of sentenceText is H

H is not a period sign so the statement inside if statement does not execute and value of i increments to 1. Now i = 1

2nd iteration:

i=1

i<size is true because i=1 and size = 35 so 1<35

So the body of loop executes:

 if (sentenceText[i]=='.') statement checks :

if (sentenceText[1]=='.')

This is the second element of sentenceText i.e. e

e is not a period sign so the statement inside if statement does not execute and value of i increments to 1. Now i = 2

So at each iteration the if condition checks if the character at i-th index of string sentenceText is a period.

Now lets see a case where the element at i-th index is a period:

6th iteration:

i=5

i<size is true because i=5 and size = 35 so 5<35

So the body of loop executes:

 if (sentenceText[i]=='.') statement checks :

if (sentenceText[5]=='.')

This is the character at 5th index of sentenceText i.e. "."

So the if condition evaluates to true and the statement inside if part executes:

sentenceText[i]='!'; statement becomes:

sentenceText[5]='!'; this means that the character at 5th position of sentenceText string is assigned an exclamation mark.

So from above 6 iterations the result is:

Hello!

This loop continues to execute until all the characters of sentenceText are checked and when the value of i gets greater than or equal to the length of sentenceText then the loop breaks.

The screenshot of the program along with its output is attached.

6 0
1 year ago
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