Answer:
i think you have written wrong equation
Step-by-step explanation:
Given:
Pyramid A: Base is rectangle with length of 10 meters and width of 20 meters.
Pyramid B: Base is square with 10 meter sides.
Heights are the same.
Volume of rectangular pyramid = (L * W * H) / 3
Volume of square pyramid = a² * h/3
Let us assume that the height is 10 meters.
V of rectangular pyramid = (10m * 20m * 10m)/3 = 2000/3 = 666.67 m³
V of square pyramid = (10m)² * 10/3 = 100m² * 3.33 = 333.33 m³
The volume of pyramid A is TWICE the volume of pyramid B.
If the height of pyramid B increases to twice the of pyramid A, (from 10m to 20m),
V of square pyramid = (10m)² * (10*2)/3 = 100m² * 20m/3 = 100m² * 6.67m = 666.67 m³
The new volume of pyramid B is EQUAL to the volume of pyramid A.
Answer:
The answer is c
I just answered the question on edunity
the diagonal of a rectangle is square root of (w^2 +l^2)
so square root of (14^2 +10^2) = 17.2 inches
since 20" is longer than 17.2 it can't be a rectangle
Answer:
Step-by-step explanation:
The sample space is known to be the set of all possible outcomes of an experiment we cannot predict its outcome while the event space showcases the subset of the sample space, this may be a collection of outcomes of a random experiment.
From the given information:
The sample space = {SH, SL, SN, MH, ML, MN,UH, UL, UN}
The event that the emissions check is satisfactory = {SH, SL, SN}
