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PilotLPTM [1.2K]
2 years ago
7

Devin volunteers at Big Pup Rescue. He is mixing up shampoo solution for the dog washing station. He needs 2 cups of shampoo con

centrate for every 9 cups of water. Devin will use 36 cups of water.
How much shampoo concentrate should Devin add to the water to make the shampoo solution?

cups of shampoo concentrate
Mathematics
2 answers:
ch4aika [34]2 years ago
7 0

Answer:

8 Shampoo Concentrate

Step-by-step explanation:

There's a ratio of 9:2 so for every 9 cups of water there's two cups of shampoo concrete.

We'll need 9 multiplied by 4 is 36

so we need to multiply 2 with 4

4 multiplied by 2 is 8

balu736 [363]2 years ago
3 0

Answer:

8. is the answer

Step-by-step explanation:

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If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i
nadya68 [22]

Answer:

  • 12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

  • 28 - 4 = 24
  • 39 - 3 = 36

<u>Lets find GCF of 24 and 36:</u>

  • 24 = 2*2*2*3
  • 36 = 2*2*3*3
  • GCF(24,36) = 2*2*3 = 12

The largest possible number of students is 12

7 0
1 year ago
List 3 rational numbers between 3 and 3.9
antiseptic1488 [7]

Answer:

its not showing up

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The velocity v of blood that flows in a blood vessel with radius r and length ℓ at a distance r from the central axis is v(r) =
pogonyaev
v(r)=4P\eta\ell(R^2-r^2)

(assuming R is the radius of the vessel, and that 0\le r\le R)

The average velocity of the blood is given by

\displaystyle\frac1{R-0}\int_{r=0}^{r=R}v(r)\,\mathrm dr
=\displaystyle\frac{4P\eta\ell}R\int_{r=0}^{r=R}(R^2-r^2)\,\mathrm dr
=\dfrac{4P\eta\ell}R\left(\dfrac23R^3\right)
=\dfrac{8P\eta\ell}3R^2
7 0
2 years ago
Gordon​ Miller's job shop has four work​ areas, A,​ B, C, and D. Distances in feet between centers of the work areas​ are: A B C
andreev551 [17]

Answer: $600,600

Step-by-step explanation:

Total handling cost :

Workpiece moved * cost * distance

Work area A :

-, (5 × 22 × 900), (9 × 22 × 900), (7 × 22 × 500)

-, 99000, 178200, 77000

Work area B:

-, -, (6 × 22 × 500), (8 × 22 × 200)

-, -, 66000, 35200

Work area C:

-, -, -, (11 × 22 × 600)

-,-,-, 145200

Work area D:

-, -, -, -

Total weekly handling cost :

(99000 + 178200 + 77000 + 66000 + 35200 + 145200)

= $600,600

Kindly check attached picture for more explanation

4 0
2 years ago
In the figure, AngleRQS Is-congruent-to AngleQLK. 3 lines are shown. Lines S P and K N are parallel. Line R M intersects line S
Lelu [443]

Answer:

x=108

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠RQS≅m∠QLK -----> by corresponding angles

m∠KLM+m∠QLK=180° -----> by supplementary angles (consecutive interior angles)

we have that

m∠RQS=x° ----> given problem

so

m∠QLX=x°

m∠KLM=(x-36)° ----> given problem

substitute

(x-36)\°+x\°=180\°\\2x=180+36\\2x=216\\x=108

5 0
2 years ago
Read 2 more answers
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