Answer:
Scenario 1 has WACC of 7.93%
Scenario 2 has WACC of 10.33%
Step-by-step explanation:
WACC=Ke*E/V+Kp*P/V+Kd(after tax)*D/V
Ke is the cost of equity =13%
Kp is the cost of preferred stock=10%
Kd(after tax) is the cost of debt of 8% adjusted for tax as below:
Kd(after tax )=Kd(before tax)*(1-t)
t is the tax rate of 30% or 0.3
Kd(after tax)=8%*(1-0.3)=5.60%
E is equity value,which is $1.8 million under scenario 1 and $3.8 under scenario 2
P is the value of preferred stock which is $1.2 million and $2.2 million respectively
D is the value of debt which is $5 million and $2 million
V=total value of capital structure=$8 million in both cases.
Scenario 1 WACC
WACC=13%*1.8/8+10%*1.2/8+5.6%*5/8=7.93%
Scenario 2 WACC
WACC=13%*3.8/8+10%*2.2/8+5.6%*2/8=10.33%
Answer:
D
Step-by-step explanation:
Answer:
<h2>One</h2>
Step-by-step explanation:
Given the value 78247 a s a stable number because at least one of its digits has the same value as its position in the number. The 4th number in the value is 4, this makes the number a stable number.
The following are the 3-digits stable numbers that appears in 78247
The first number is 824. This digits are stable numbers because 2 as a number is situated in the same place as the number (2nd position).
Hence, there are only 1 stable 3-digit numbers in the value 78247 since only a value exists as 2 in the value and there is no 1 and 3 in the value.
90 inches 18 times 5 is 90 and 30 times 3 is 90 so the lowest point which they will be at the height is 90 inches
Answer:
A. $301
B. $721
Step-by-step explanation:
Let $x be the amount of money they raised.
Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then
Polly tried to put the $1 bills into three equal piles and found one left over at the end, then
Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then
Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then
This means 
is divisible by 2, 3, 4, 5 and 6 without remainder, so
Hence,
The smallest amount of money they could have raised is $301, because
is divisible by 7.
Now, the number 
should be divisible by 7 and must be greater than 500.
So,
When n = 9,
is not divisible by 7.
When n = 10,
is not divisible by 7.
When n = 11,
is not divisible by 7.
When n = 12,
is divisible by 7.
B. The least amount of money they could have raised is $721
