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tigry1 [53]
2 years ago
15

Complete the table to find 430 percent of 90. A 2-column table with 6 rows. Column 1 has entries 100 percent, 100 percent, 100 p

ercent, 100 percent, 30 percent, Total 430 percent. Column 2 has entries 90, 90, 90, 90, A, Total B. A = B=
Mathematics
2 answers:
Aneli [31]2 years ago
7 0

Answer:

Complete the table to find 430 percent of 90.

A 2-column table with 6 rows. Column 1 has entries 100 percent, 100 percent, 100 percent, 100 percent, 30 percent, Total 430 percent. Column 2 has entries 90, 90, 90, 90, A, Total B.

A =

✔ 27

B=

✔ 387

I copied and pasted it from edg.

salantis [7]2 years ago
4 0

Answer:

A= 27

B=387

Step-by-step explanation:

i just did the quiz

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Cameron buys 2.45 pounds of apples and 1.65 pounds of pears. Apples and pears each cost c dollars per pound. If the total cost a
Leto [7]

Answer:

2.45c + 1.65c = 4.12 + 0.75

Step-by-step explanation:

To write an equation to find the value for c, we need to declare what c is first.

c = price of fruit

2.45c + 1.65c = 4.12 + 0.75

Now we multiplied c to 2.45 and 1.65 and added them together, because whatever the value of c is will give us the equivalence of the sum of 4.12 + 0.75.

Now to check if the equation is right, let's solve for c.

2.45c + 1.65c = 4.12 + 0.75

4.1c = 4.87

Now to get the value of c, we divide both sides of the equation by 4.1.

\dfrac{4.1c}{4.1}=\dfrac{4.87}{4.1}

c = 1.19

Now let's substitute the value of c in the equation to see if we got it right.

2.45(1.19) + 1.65(1.19) = 4.12 + 0.75

2.92 + 1.96 = 4.87

4.87 = 4.87

Therefore concluding that the value of c is 1.19.

7 0
2 years ago
Last year your professor wanted to study the pattern in class grades. The following table contains a sample of grades collected
Maslowich

Answer:

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

Step-by-step explanation:

<u>Mean:-</u>

The mean (average) is found by adding all of the numbers together and dividing by the number of items and it is denoted by x⁻

                                                                                                                           mean =  \frac{64+80+75+98+75}{5}

mean (x⁻ ) = 78.4

The mean of the given data = 78.4

<u>Median:</u>

The median is found by ordering the set from lowest to highest and finding the exact middle.

64 ,75, 80, 98

The middle term of the given data set = \frac{75+80}{2} =77.5

<u>Mode :</u>

The mode is the most common repeated number in a data set.

64 ,75, 75, 80, 98

in data the most common number = 75

<u>Conclusion</u>:-

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

   

8 0
1 year ago
To the nearest degree, what is the measure of the central angle for faucets? 37° 24° 48° 43°
Masteriza [31]

Answer:

\large\boxed{43^o}

Step-by-step explanation:

\text{Faucets}\to12\%\\\\p\%=\dfrac{p}{100}\to12\%=\dfrac{12}{100}=0.12\\\\12\%\ \text{of}\ 360^o\to0.12\cdot360^o=43.2^o\approx43^o

4 0
2 years ago
Read 2 more answers
What is the GCF of x2 and x9?​
zepelin [54]

Answer:

x²

Step-by-step explanation:

Given the values x² and x^9

The greatest common factor is the factors common to two or more compared values :

Factors of :

x² = x * x

x^9 = x * x * x * x * x * x * x * x * x

Multiplying the Factors in both are : x * x = x²

Similarly :

___|x² | x^9

_ x | x | x^8

_ x | 1 | x^7

There is no factor which can reduce both further simultaneously, Hence the G. C. F = (x * x) = x²

3 0
2 years ago
A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
2 years ago
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