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stiv31 [10]
2 years ago
9

A bag of apples weighs 7 7/8 pounds and a full bag costs $10.88. By weight 1/18 of the apples are rotten . What is the cost of t

he bag if the bad apples are removed?
 
Mathematics
2 answers:
ioda2 years ago
7 0
Try Analysing The Information Like This, Step by Step;

1. We know that a full bag of 7 7/8 pounds and is $10.88.
2. Now we subtract the bad apples 7 7/8-1/18= a (now we have no bad apples).
3. Part 'a' answer will give you a no. in pounds.
4. Part 'b' - we have to find out $10.88/7 7/8 - 1/18 / 2 to give you the answer.

I hope this helps, sorry I couldn't really help you :)
SashulF [63]2 years ago
4 0

Answer: Hello there!

We know that a bag of apples weighs (7 + 7/8) lb  and costs $10.88

But 1/18 of the apples are rotten, if we remove the rotten apples, we still have the other 17/18 portion of the bag to pay.

then; if the full bag costs $10.88, how much does it cost a 17/18 of the bag?

this is (17/18)*$10.88 = $10.28

Then if you remove 1/18 of the apples, the bag costs 10.28 dollars.

notice that I did not use the weight of the apples, in a lot of math problems you will have more information than the needed, and you need to know when the information is useful and when it is not.

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What kind of salad do snowmen eat? Punchline 73 answer key
motikmotik

Answer:

Coldslaw

Step-by-step explanation:

6 0
2 years ago
Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. How many total kilograms of candy did he buy?
nignag [31]

Answer:

1.26 kg.

Step-by-step explanation:

We have been given that Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. We are asked to find the amount of candy bought by Mr. Snow in kilograms.

First of all, we will find the amount of candy in grams by multiplying 90 grams by 14 as:

\text{Amount of candy bought in grams}=14\times 90

\text{Amount of candy bought in grams}=1260

We know that 1 kilogram is equal to 1000 grams. To convert 1260 grams into kg, we will divide 1260 by 1000 as:

\text{Amount of candy bought in kilograms}=\frac{1260}{1000}

\text{Amount of candy bought in kilograms}=1.26

Therefore, Mr. Snow bought 1.26 kilograms of candy.

7 0
2 years ago
Consider that 1 inch = 2.54 centimeters. Which three statements are true for converting 18 feet to centimeters?
serg [7]

Answer:

There are 548.64 cm in 18 feet.

Step-by-step explanation:

We know that, 1 inch = 2.54 centimeters.

We need to convert 18 feet to centimeters

Also, 1 foot = 12 inch

Firstly we will convert 18 feet to inch.

18 feet = 12 × 18 inch

= 216 inch

Now to convert 18 feet to centimeters, multiply 216 inch by 2.54 cm as follows :

216 inch = 2.54×216 centimeters

= 548.64 cm

Hence, there are 548.64 cm in 18 feet.

4 0
2 years ago
the diameter of a football is five times the diameter of a cricket ball ratio of surface area of football and cricket ball is​
LenKa [72]

Answer:

25 : 1

Step-by-step explanation:

The diameter of the football is 5 times the diameter of the cricket ball. This means that the radius of the football is also 5 times the radius of the cricket ball.

Let the radius of the football be R.

Let the radius of the cricket ball be r.

This implies that:

R = 5r

Both balls are spherical.

The surface area of the cricket ball is given as:

a = 4\pi r^2

The surface area of the football is given as:

A = 4\pi R^2

=>A = 4\pi (5r)^2\\\\A = 100\pi r^2

Therefore, the ratio of their surface areas is:

A : a

100\pi r^2 : 4\pi r^2

= 100 : 4

25 : 1

5 0
2 years ago
The center of a circle is at the origin on a coordinate grid. The vertex of a parabola that opens upward is at (0, 9). If the ci
zhannawk [14.2K]

Answer:

"The maximum number of solutions is one."

Step-by-step explanation:

Hopefully the drawing helps visualize the problem.

The circle has a radius of 9 because the vertex is 9 units above the center of the circle.

The circle the parabola intersect only once and cannot intercept more than once.  

The solution is "The maximum number of solutions is one."

Let's see if we can find an algebraic way:

The equation for the circle given as we know from the problem without further analysis is so far x^2+y^2=r^2.

The equation for the parabola without further analysis is y=ax^2+9.

We are going to plug ax^2+9 into x^2+y^2=r^2 for y.

x^2+y^2=r^2

x^2+(ax^2+9)^2=r^2

To expand (ax^2+9)^2, I'm going to use the following formula:

(u+v)^2=u^2+2uv+v^2.

(ax^2+9)^2=a^2x^4+18ax^2+81.

x^2+y^2=r^2

x^2+(ax^2+9)^2=r^2

x^2+a^2x^4+18ax^2+81=r^2

So this is a quadratic in terms of x^2

Let's put everything to one side.

Subtract r^2 on both sides.

x^2+a^2x^4+18ax^2+81-r^2=0

Reorder in standard form in terms of x:

a^2x^4+(18a+1)x^2+(81-r^2)=0

The discriminant of the left hand side will tell us how many solutions we will have to the equation in terms of x^2.

The discriminant is B^2-4AC.

If you compare our equation to Au^2+Bu+C, you should determine A=a^2

B=(18a+1)

C=(81-r^2)

The discriminant is

B^2-4AC

(18a+1)^2-4(a^2)(81-r^2)

Multiply the (18a+1)^2 out using the formula I mentioned earlier which was:

(u+v)^2=u^2+2uv+v^2

(324a^2+36a+1)-4a^2(81-r^2)

Distribute the 4a^2 to the terms in the ( ) next to it:

324a^2+36a+1-324a^2+4a^2r^2

36a+1+4a^2r^2

We know that a>0 because the parabola is open up.

We know that r>0 because in order it to be a circle a radius has to exist.

So our discriminat is positive which means we have two solutions for x^2.

But how many do we have for just x.

We have to go further to see.

So the quadratic formula is:

\frac{-B \pm \sqrt{B^2-4AC}}{2A}

We already have B^2-4AC}

\frac{-(18a+1) \pm \sqrt{36a+1+4a^2r^2}}{2a^2}

This is t he solution for x^2.

To find x we must square root both sides.

x=\pm \sqrt{\frac{-(18a+1) \pm \sqrt{36a+1+4a^2r^2}}{2a^2}}

So there is only that one real solution (it actually includes 2 because of the plus or minus outside) here for x since the other one is square root of a negative number.

That is,

x=\pm \sqrt{\frac{-(18a+1) \pm \sqrt{36a+1+4a^2r^2}}{2a^2}}

means you have:

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+4a^2r^2}}{2a^2}}

or

x=\pm \sqrt{\frac{-(18a+1)-\sqrt{36a+1+4a^2r^2}}{2a^2}}.

The second one is definitely includes a negative result in the square root.

18a+1 is positive since a is positive so -(18a+1) is negative

2a^2 is positive (a is not 0).

So you have (negative number-positive number)/positive which is a negative since the top is negative and you are dividing by a positive.

We have confirmed are max of one solution algebraically. (It is definitely not 3 solutions.)

If r=9, then there is one solution.

If r>9, then there is two solutions as this shows:

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+4a^2r^2}}{2a^2}}

r=9 since our circle intersects the parabola at (0,9).

Also if (0,9) is intersection, then

0^2+9^2=r^2 which implies r=9.

Plugging in 9 for r we get:

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+4a^2(9)^2}}{2a^2}}

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+324a^2}}{2a^2}}

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{(18a+1)^2}}{2a^2}}

x=\pm \sqrt{\frac{-(18a+1)+18a+1}{2a^2}}

x=\pm \sqrt{\frac{0}{2a^2}}

x=\pm 0

x=0

The equations intersect at x=0. Plugging into y=ax^2+9 we do get y=a(0)^2+9=9.  

After this confirmation it would be interesting to see what happens with assume algebraically the solution should be (0,9).

This means we should have got x=0.

0=\frac{-(18a+1)+\sqrt{36a+1+4a^2r^2}}{2a^2}

A fraction is only 0 when it's top is 0.

0=-(18a+1)+\sqrt{36a+1+4a^2r^2}

Add 18a+1 on both sides:

18a+1=\sqrt{36a+1+4a^2r^2

Square both sides:

324a^2+36a+1=36a+1+4a^2r^2

Subtract 36a and 1 on both sides:

324a^2=4a^2r^2

Divide both sides by 4a^2:

81=r^2

Square root both sides:

9=r

The radius is 9 as we stated earlier.

Let's go through the radius choices.

If the radius of the circle with center (0,0) is less than 9 then the circle wouldn't intersect the parabola.  So It definitely couldn't be the last two choices.

7 0
2 years ago
Read 2 more answers
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