Answer:
Step-by-step explanation:
Hello!
X₁: speed of a motorcycle at a certain intersection.
n₁= 135
X[bar]₁= 33.99 km/h
S₁= 4.02 km/h
X₂: speed of a car at a certain intersection.
n₂= 42 cars
X[bar]₂= 26.56 km/h
S₂= 2.45 km/h
Assuming
X₁~N(μ₁; σ₁²)
X₂~N(μ₂; σ₂²)
and σ₁² = σ₂²
<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>
The parameter of interest is μ₁-μ₂
(X[bar]₁-X[bar]₂)±
* 
[(33.99-26.56) ± 1.654 *(
)]
[6.345; 8.514]= [6.35; 8.51]km/h
<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>
[(475.12-321.34) ± 2.485 *(
)]
[121.96; 185.60]
I hope this helps!
Answer:
177 $
Step-by-step explanation:
20 x8 = 160
3x3= 9
4x2=8
8+9+160= 177
Answer:
Step-by-step explanation:
we know that
If CD is parallel to XZ
then
Triangle XYZ is similar to Triangle YCD
therefore
The ratio of their corresponding sides are equal
we have
CX=5\ units, CY=25\ units, YD=20\ units,
substitute the values
700 - 175 is equal to 525 when you divide that by 35 you get 15 which is your answer.
Yesterday Hadi earned: $120
Today he will earn: $120*85% = $102
(You times the amount yesterday by 85% because you want to find the 15% less of 100% of the amount he's earned yesterday. Therefore, to find 15% less than yesterday you multiply it by 85% (100% - 15%) )
Tomorrow he will earn: $102*115% = $117.30
(Same thing here, however you are finding 15% more than 100% today. Therefore, you multiply the amount he earned today it by 115% (100% + 15%) )
To find the amount he earns for the three days you must add the amount earned of yesterday, today and tomorrow earned from the working above.
Therefore, Hadi expects to earn:
Yesterday + Today + Tomorrow = 120 + 102 + 117.30 = $339.3
