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REY [17]
1 year ago
13

Elizabeth runs a farm stand that sells apples and raspberries. Each pound of apples sells for $2.25 and each pound of raspberrie

s sells for $1.50. Elizabeth sold 32 more pounds of raspberries than pounds of apples and made $108 altogether. Graphically solve a system of equations in order to determine the number of pounds of apples sold, x, and the number of pounds of raspberries sold,y.
Mathematics
1 answer:
mixas84 [53]1 year ago
3 0

Answer:

Im confused?

Step-by-step explanation:

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The price of a box of 15 cloud markers is $12.70. The price of a box of 42 cloud markers is $31.60. All prices are without tax,
stich3 [128]

Answer:  

Here, The price of one box having N markers = Price of N markers + packaging charge

Let M be the price of one Marker and P' be the price of packaging of one box which is same for any size.

Since, The price of a box of 15 cloud markers is $12.70.

That is , 15 M + P' = 12.70 ---------(1)

Also,  The price of a box of 42 cloud markers is $31.60,

That is, 42 M + P' = 31.60 ---------(2),

Equation (2) - Equation (1),

27 M = 18.90,

⇒ M = 0.7

By putting the value of P in equation (1),

We get,

10.5 + P' = 12.70 ⇒ P' = 2.2,

Thus, the price of one marker, M = 0.7

And, the price of packaging one box, P' = 2.2

Thus, the price of a box of 50 marker = 50 × M + P' = 50×0.7 + 2.2 = 35 + 2.2 = $ 37.2

And, the equation that shows the price(P) of a box of N markers,

P = 0.7 N + 2.2

3 0
2 years ago
Read 2 more answers
As part of Kayla's exercise program,she either runs 6miles/day or rides her bike 10 miles/day.Her new goal is to cover a minimum
poizon [28]
6(15) + 10b > = 200
90 + 10b > = 200
10b > = 200 - 90
10b > = 110
b > = 110/10
b > = 11

so she can do 15 days of running plus 11 days of biking....which totals 26 days

8 0
2 years ago
Find the value of y for which the value of 1.7y+37 is 14 less than the value of 9.3y–25 HELP QUICK
Harrizon [31]

Answer:

y=10

Step-by-step explanation:

1.7y+37 is 14 less than the value of 9.3y–25

  • 1.7y + 37 = 9.3y - 25 - 14
  • 1.7y + 37 = 9.3y - 39
  • 9.3y - 1.7y = 37 + 39
  • 7.6y = 76
  • y = 76/7.6
  • y = 10

Answer is 10

4 0
2 years ago
a(0.3−y)+1.1+2.4x (y−1.2) ​ =0 =−1.2(x−0.5) ​ Consider the system of equations above, where aaa is a constant. For which value o
Veseljchak [2.6K]

Answer:

For a = 1.22 there is one solution where y = 1.3

Step-by-step explanation:

Hi there!

Let´s write the system of equations:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

-1.2(x-0.5) = 0

Let´s solve the second equation for x:

-1.2(x-0.5) = 0

x- 0.5 = 0

x = 0.5

Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0

a(-1) + 1.1 + 1.2(0.1) = 0

-a + 1.22 = 0

-a = -1.22

a = 1.22

Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:

1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0

0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0

-0.02y +0.026 = 0

-0.02y = -0.026

y = -0.026 / -0.02

y = 1.3

Then, the answer is correct.

Have a nice day!

4 0
2 years ago
a used car dealer has a vehicle on the lot with a sticker price of $9999. if the dealer markup on used vehicles is 15%, how much
shepuryov [24]
$8694.78

Hope this helps!
5 0
2 years ago
Read 2 more answers
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