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OlgaM077 [116]
1 year ago
4

Write 243 as a repeated multiplication of 3s.

Mathematics
1 answer:
viva [34]1 year ago
5 0

Answer:

i think its 3x3x3x3x3

Step-by-step explanation:

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The eastward translation of the rose garden is along which axis? What integer represents a change of two yards east?
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a) + x direction, b) +2\,yd.

Step-by-step explanation:

a) According to the Cartesian plane, an eastward translation implies a movement in the +x direction.

b) +2\,yd

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Table below represents average food cost broken down by meal. If you were
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D

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I think D at all timessz

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Tonya plans to join a fitness club. She researched the costs to join different clubs in her area and found that there is a linea
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Answer: The correct answer is 1

Step-by-step explanation:

4 0
2 years ago
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Setting StartFraction 7 over 3 EndFraction equal to which ratio would result in a valid proportion?
pochemuha

Answer:

Option C is correct

Step-by-step explanation:

In this question, we are asked to select which of the options have the same value as 7/3

We examine the options one urge other.

Option A

9/49; This is wrong as it cannot be divided further to yield while multiples

Option B

18/42; Dividing through by 6 will yield 3/7 which is not same as 7/3; This makes this option wrong too

Option C

42/18; dividing through by 6 will yield 7/3 which makes this option correct

Option D

49/9; This is a dead end as it cannot be divided further to give whole number multiples

6 0
2 years ago
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Consider a tank in the shape of an inverted right circular cone that is leaking water. The dimensions of the conical tank are a
Artyom0805 [142]

Answer:

\frac{dh}{dt} = \frac{216}{1875\pi}

Step-by-step explanation:

Given

Represent radius with r and height with h

h = 12ft

r = 10ft

Rate = \frac{8ft^3}{min} when h = 10ft

Express radius in terms of height

\frac{r}{h} = \frac{10}{12}

\frac{r}{h} = \frac{5}{6}

r = \frac{5}{6}h

First, we need to determine the volume of the cone in terms of height.

Volume = \frac{1}{3}\pi r^2h

Substitute r = \frac{5}{6}h

V = \frac{1}{3} * \pi * (\frac{5}{6}h)^2 * h

V = \frac{1}{3} * \pi * \frac{25}{36}h^2 * h

V = \frac{1}{3} * \pi * \frac{25}{36}h^3

V = \frac{25}{108} \pi h^3

Differentiate both sides w.r.t time (t)

\frac{dV}{dt} = 3 *  \frac{25}{108} \pi h^{3-1} * \frac{dh}{dt}

\frac{dV}{dt} = \frac{75}{108} \pi h^{2} \frac{dh}{dt}

Solve for \frac{dh}{dt}

\frac{dh}{dt} = \frac{dv}{dt} * \frac{108}{75\pi h^2}

At this point, h = 10 and \frac{dv}{dt} = \frac{8ft^3}{min}

So, we have:

\frac{dh}{dt} = 8 * \frac{108}{75\pi 10^2}

\frac{dh}{dt} = \frac{8 * 108}{75\pi 10^2}

\frac{dh}{dt} = \frac{864}{7500\pi}

\frac{dh}{dt} = \frac{216}{1875\pi}

Hence:

The rate is \frac{216}{1875\pi} ft/min

6 0
2 years ago
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