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2 years ago

7

Old Granny Adams left half her money to her granddaughter and half that amount to her grandson. She left a sixth to her brother,

and the remainder, $1,000, to the dogs’ home. How much did she leave altogether?
Good Luck!!! First Right Answer gets brainliest!!!

2 answers:

Y_Kistochka [10]2 years ago

7 0

She left $12,000! she left the granddaughter $6,000 and her grandson $3,000 and her brother $2,000 the rest ($1,000) to the dogs home

dmitriy555 [2]2 years ago

6 0

Answer:: She left $12,000.

Step-by-step explanation:

$12,000

Old Granny Adams left half her money to her granddaughter and half that amount to her grandson. She left a sixth to her brother, and the remainder, $1,000, to the dogs' home. How much did she leave altogether?

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A chef has 14 brands of hot sauce. In how many ways can the chef pick 3 to mix into a gumbo

Sloan [31]

Answer:

364ways

Step-by-step explanation

This is a problem on combination. Combination has to do with selection. For example if r objects are to be selected from a pool of n objects, this can be done in nCr ways.

nCr = n!/(n-r)!r!

If a brand has 14brands of hot sauce and he is to pick 3 to mix into a gumbo, he can select those 3 from a pool of 14brands in 14C3 number of ways.

14C3 = 14!/(14-3)!3!

14C3 = 14!/11!3!

14C3 = 14×13×12×11!/11!×6

14C3 = 14×13×12/6

14C3 = 14×26

14C3 = 364ways

8 0

2 years ago

The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds

Bumek [7]

Answer: 11.5%

Explanation:

Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds.

Now, we get the z-score for 720 seconds by the following formula:

$\text{z-score} = \frac{x - \mu}{\sigma}$

where

$t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}$

So, the z-score of 720 seconds is given by:

$\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}$

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

$P(t \ \textgreater \ 720) 
\\ = P(z \ \textgreater \ 1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\ \boxed{P(t \ \textgreater \ 720) = 0.115}$

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice.

8 0

2 years ago

A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random

Akimi4 [234]

Answer:

$t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70$

The degrees of freedom are given by:

$df=n-1=14-1=13$

The p value for this case would be given by:

$p_v =P(t_{(13)}$

Step-by-step explanation:

Information given

$\bar X=24$ represent the mean height for the sample

$s=2.2$ represent the sample standard deviation

$n=14$ sample size

$\mu_o =25$ represent the value that we want to test

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to verify

We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:

Null hypothesis: $\mu \geq 25$

Alternative hypothesis: $\mu < 25$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70$

The degrees of freedom are given by:

$df=n-1=14-1=13$

The p value for this case would be given by:

$p_v =P(t_{(13)}$

8 0

2 years ago

As a self-employed seamstress, you know that it takes 7 yards of material to make 3 jackets. You bought 15 yards of material to

4vir4ik [10]

Answer:

you bought a little bit less than you needed

Step-by-step explanation:

so if it takes 7 yards to make three jackets and you have 15 yards this is what you have to do:

7 yards=3 jackets

7+7=14 so with 14 yards you can make 6 jackets

but you bought fifteen and 7 divided 3 equals 2.3 ( or what it takes to make one jacket)

so if you wanted to have exactly enough material to make 7 jackets you need 16.3 yards

3 0

2 years ago

Read 2 more answers

A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like

mixas84 [53]

Answer:

a) $\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) $\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) the steady state mass of the drug is 2000 mg

d) t ≅ 153.51 minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

$Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min$

$Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min$

Therefore;

$\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}$

with respect to x(0) = 0

$\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

$\dfrac{dx}{dt} = -0.015(x - 2000)$

$\dfrac{dx}{(x - 2000)} = -0.015 \times dt$

By Using Integration Method:

$ln(x - 2000) = -0.015t + C$

$x -2000 = Ce^{(-0.015t)$

$x = 2000 + Ce^{(-0.015t)}$

However; if x(0) = 0 ;

Then

C = -2000

Therefore

$\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

$\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}$

x = 2000 - 0

x = 2000

Thus; the steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

$\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}$

$0.1 = e^{(-0.015t)$

$ln(0.1) = -0.015t$

$t = -\dfrac{In(0.1)}{0.015}$

t = 153.5056729

t ≅ 153.51 minutes

4 0

2 years ago