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Umnica [9.8K]
2 years ago
5

The shape is composed of three squares and two semicircles.Select all the expressions that correctly calculate the perimeter of

the shape
Mathematics
1 answer:
lidiya [134]2 years ago
3 0

Answer:

100+20π

Step-by-step explanation:

Find the diagram attached.

Perimeter of a square =4L

L is the side length of a square

From the diagram;

L = 10

Perimeter of a square = 4(10) = 40

Perimeter of 3 squares = 3(40) = 120

2 semi circle = a circle

Perimeter of a circle= 2πr

radius of the Circle = length of a side of the square.

Area of the circle = 2π(10)= 20π

Perimeter of the shape = Perimeter of the two semicircle + area of the 4squares = 100+20π

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Alison wants to distribute the carnations and roses equally among the 6 flower shops. Factor the expression from Part A using 6
mixer [17]

Answer:

6

Step-by-step explanation:

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2 years ago
Mike took 12 shots with a basketball and made 9. This can be expressed as a decimal as 0.75. What other person’s successful shot
dimulka [17.4K]
I baseball player swung at the ball 100 times and only made conract 75 times this could be exspressed as 0.75 
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5 0
2 years ago
Solve the triangle. A = 46° a = 33 b = 26
frozen [14]
Using sin rule:
a/sin A =b/sin B=c/sin c
SIN A=sin 46=0.72
THEN:sin B =(0.72*26)/33=0.57
then B= 34° 
AS the sum of triangle angles=180 
then C=180-(46+34)=100°
then c =(a*sin C)/sin A
sin C=sin 100=0.98
=(33*0.98)*0.72=45
7 0
3 years ago
Read 2 more answers
PLEASE HELP TO SOLVE QUESTION with full process c) Mr. Thapa bought a motorbike for Rs 1,25,000 and fixed its price 20 % above t
klasskru [66]

Answer: Rs. 1,52,550

Step-by-step explanation:

CP of motorcycle = 125000

Selling Price fixed = 125000 + 20% = 150000

10% discount = 150000*10% = 15000

SP after 10% discount

= 150000-15000= 135000

VAT at 13% = 135000 * .13 = 17550

Mr Gurung paid total

135000 + 17550 = 152550

8 0
2 years ago
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Identify the 12th term of the arithmetic sequence in which a7 = 40 and a18 = 106.
Lady_Fox [76]

we are given

airthematic sequence

we can use nth term formula

a_n=a_1+(n-1)d

n is number of terms

an is nth term

d is common difference

a1 is first term

We are given

a7=40

we can use it

a_7=a_1+(7-1)d

40=a_1+6d

a_1+6d=40

a18 = 106

a_1_8=a_1+(18-1)d

a_1+17d=106

we can subtract both equations

a_1+17d-a_1-6d=106-40

11d=66

d=6

now, we can find a1

a_1+6d=40

we can plug d=6

a_1+6*6=40

a_1=4

12th term:

a_1_2=a_1+(12-1)d

now, we can plug values

a_1_2=4+(12-1)*6

a_1_2=4+66

a_1_2=70

so, 12th term is 70...........Answer

3 0
2 years ago
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