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Vesna [10]
1 year ago
7

A veterinarian is interested in the average number of pets her clients own. Over the course of a month, she questions each clien

t she meets with and records their responses. The veterinarian calculates the average and draws a conclusion from her data.
What kind of statistical study did the veterinarian conduct?

A.
theoretical study
B.
survey
C.
experiment
D.
observational study
Mathematics
1 answer:
Law Incorporation [45]1 year ago
4 0
I’m pretty sure the answer is B. survey.
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The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

7 0
1 year ago
27 students are learning to make balloon animals. There are 172 balloons to be shared equally among the students
bija089 [108]
A.) .4 of a balloon is left
To Check:
what I did was divide 172 by 27 and it is 6.37 rounded to ........6 is an equal number so I kept it and .4 will be left over after sharing equally.

B.) 17 more balloons are needs
To Check:
what I was multiply 27 by 7 because each student needs seven balloons and I got 189 after that I subtracted 172 from 189 (189-172=17)
to see how many more balloons are needed.
3 0
1 year ago
Read 2 more answers
Peter wants to put 2 coats of paint on both the inside and outside of the walls. There are 5 walls, each side having 45 ft2 of p
Lelechka [254]
I have no clue man hhhhhhhhhhhhhh
5 0
1 year ago
Read 2 more answers
Bella bought 3.2 meters of ribbon to decorate her pencil case. each meter cost $0.46. how much did the ribbon cost?
zlopas [31]

we know that

Each meter of ribbon cost \$0.46  

so

by proportion

Find the cost of 3.2 meters of ribbon

\frac{0.46}{1} \frac{\$}{meter} =\frac{x}{3.2} \frac{\$}{meter} \\ \\x=3.2*0.46 \\ \\x=\$1.472

therefore

<u>the answer is</u>

The ribbon cost \$1.472


8 0
1 year ago
Read 2 more answers
Charles is reading about computers. He learns that a computer processor can perform one command in approximately 0.000000016
ella [17]

<em><u>The number 0.000000016 is expressed in scientific notation is:</u></em>

1.6 \times 10^{-8}

<em><u>Solution:</u></em>

Given that,

Charlie learns that a computer processor can perform one command in approximately 0.000000016  nanoseconds

We have to express in scientific notation

<em><u>Step 1:</u></em>

Given number is:

0.000000016

Move the decimal point in 0.000000016 until there is only one non-zero digit to the left of the decimal point

Here,

Move the decimal 8 places to the right to get 1.6

We have moved the decimal to left, therefore, exponent is negative

1.6 \times 10^{-8}

Thus the given number is expressed in scientific notation

8 0
1 year ago
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