If P(x 3), Q(7, -1) and PQ= 5 units, find the possible value of x.

Mathematics

1 answer:

Neporo4naja [7]1 year ago

5 0

Given :

P(x 3), Q(7, -1) and PQ= 5 .

To Find :

The possible value of x.

Solution :

We know, distance between two points in coordinate plane is given by :

$PQ = \sqrt{(x-7)^2 + ( 3-(-1))^2}\\\\PQ^2 = (x-7)^2 + ( 3-(-1))^2\\\\(x-7)^2 + 4^2 = 5^2\\\\( x- 7)^2 = 3^2 \\\\x - 7 = \pm 3\\\\x = 10 \ and \ x = 4$

Therefore, the possible value of x are 10 and 4.

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Ede4ka [16]

Answer:

Step-by-step explanation:

Given is a function in x as

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4 0

2 years ago

On Saturday, Craig rode his bike 5/8 of a mile. On Saturday, he rode his bike 1/2 of a mile. Craig added 5/8+1/2=6/10and plotted

VashaNatasha [74]

* Craig's answer is not reasonable because to add fractions the denominators must be the same.

** Total distance = 5/8 + 1/2 = 5/8 + 4/8 = 9/8 miles

*** Using the line number to prove the answer:
The line number that represents the problem is in the attached figure.
while the distance between 0 and 1 divided to 8 sections
to represent (5/8) count 5 sections from zero ⇒⇒⇒ point (a)
and to represent (1/2) it is the midpoint between 0 and 1 which mean it is 4 sections but it will be counted from point (a) so, adding 4 sections to point (a) the result will be the point (b)
So, counting from 0 to point (b) will give us 9 sections
and while one section represents (1/8)
So the total distance will be 9 * (1/8) = 9/8 which is agree with the result obtained before