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vodomira [7]
2 years ago
3

Parallel lines e and f are cut by transversal b. Horizontal and parallel lines e and f are cut by transversal b. At the intersec

tion of lines b and e, the uppercase right angle is (2 x + 10) degrees. At the intersection of lines b and f, the bottom left angle is (3 x minus 15) degrees. What is the value of x?
Mathematics
1 answer:
densk [106]2 years ago
3 0

Answer:

x = 25

Step-by-step explanation:

Alternate exterior angles are equal.

3x - 15 = 2x +10

3x        = 2x + 10 + 15

3x - 2x = 25

         x = 25

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A survey of 125 households was done to investigate whether households have laptops, tablets, or
riadik2000 [5.3K]

Answer:

3) 0.326

Step-by-step explanation:

Total Number of surveyed households =125

We want to determine the probability that a randomly selected household would have a laptop given that it does not  have a tablet.

Written in Probability notation: P(Laptop|No Tablet)

P(Laptop|No Tablet)=\dfrac{P(L\cap T')}{P(T')} \\=\dfrac{31/125}{95/125}\\=\dfrac{31}{95}\\\\=0.326

The correct option is C,

4 0
2 years ago
Andy takes a computer course exam He scores 53 marks out of 75. the table shows the result obtained based on the percentage in t
xeze [42]
A) 70.7%
Explanation 53/75 * 100
B) Merit
4 0
2 years ago
Read 2 more answers
• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
2 years ago
What is the surface area of the regular pyramid below
Alenkinab [10]

S=14\times14+4(\frac{14}{2}\times18) \\S=196+4(7\times18) \\S=196+4\times126 \\S=196+504 \\S=\boxed{700}

5 0
2 years ago
Read 2 more answers
The most popular mathematician in the world is throwing aparty for all of his friends. As a way to kick things off, they decidet
ratelena [41]

Answer:

The no. of possible handshakes takes place are 45.

Step-by-step explanation:

Given : There are 10 people in the party .

To Find: Assuming all 10 people at the party each shake hands with every other person (but not themselves, obviously) exactly once, how many handshakes take place?

Solution:

We are given that there are 10 people in the party

No. of people involved in one handshake = 2

To find the no. of possible handshakes between 10 people we will use combination over here

Formula : ^nC_r=\frac{n!}{r!(n-r)!}

n = 10

r= 2

Substitute the values in the formula

^{10}C_{2}=\frac{10!}{2!(10-2)!}

^{10}C_{2}=\frac{10!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 \times 8!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 }{2 \times 1}

^{10}C_{2}=45

No. of possible handshakes are 45

Hence The no. of possible handshakes takes place are 45.

4 0
2 years ago
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