Question

Find the solution set of the inequality. \qquad16x - 7 \leq -7116x−7≤−71

Answer 1

Answer:

$x \le -4$

Step-by-step explanation:

Given

$\qquad16x - 7 \leq -71$

Required

Solve

Start by adding 7 to both sides

$\qquad16x - 7 + 7 \leq -71 + 7$

$\qquad16x - 7 + 7 \leq -64$

$\qquad16x \leq -64$

Divide both sides by 16

$\frac{16x}{16} \leq \frac{-64}{16}$

$\frac{16x}{16} \leq -\frac{64}{16}$

$x \leq -\frac{64}{16}$

$x \le -4$ --- The solution

Answer 2

Answer:

x < -4

I did this on khan academy