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MrRa [10]
2 years ago
10

Elisse has 20 meters of ribbon how many 15 cm of ribbon can be cut from it

Mathematics
1 answer:
ASHA 777 [7]2 years ago
8 0

Answer:

133 pieces of 15cm can be cut from the ribbon.

Step-by-Step Explanation:

Length of ribbon = 20 meters

Length needed to be cut = 15 cm

We will convert meters into centimeters.

1 meter = 100 cm

20 meters = 2000 cm

Number of pieces = \frac{2000}{15}

Number of pieces = 133.33

Rounding off to nearest whole number = 133

Hence,

133 pieces of 15cm can be cut from the ribbon.

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In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution 


We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ +  v₂c₂
40(0.32) = 10(0.2) + 30c
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2 years ago
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Nathan is out rafting. He rafts 16 miles with the river current. At the end of 16 miles, he turns around and rafts the same dist
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S = d/t

st = d

t = d/s

The time going is t1.
The time returning is t2.
The total time is 4 hours, so we have t1 + t2 = 4

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The speed going is 9 + c.
The speed returning is 9 - c.

t1 = 16/(9 + c)

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4 = 16/(9 - c) + 16/(9 + c)

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Answer:

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The function f(x) = 1/2 x + 3/2 is used to complete this table.
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Answer:

a) f(-1/2)  = -2 is NOT TRUE.

b)  f(0)  =3/2 is  TRUE.

c)   f(1)  = -1 is NOT TRUE.

d)   f(2)  = 1 is NOT TRUE.

e)   f(4)  = 7/2  is  TRUE.

Step-by-step explanation:

Here, the given function is  f(x) = (\frac{1}{2}) x+\frac{3}{2}

Now, checking for each values for the given function:

a) Putting x  = (-1/2):

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and (5/4) ≠  -2

Hence, f(-1/2)  = -2 is NOT TRUE.

b)Putting x  = 0 :

f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )

Hence, f(0)  =3/2 is  TRUE.

c) Putting x  = 1:

f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2}   = \frac{1}{2}  + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2}  = (\frac{4}{2} )   = 2\implies 2   \neq -1

Hence, f(1)  = -1 is NOT TRUE.

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and (5/2) ≠  1

Hence, f(2)  = 1 is NOT TRUE.

e)Putting x  = 4:

 f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2}   = 2  + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2}  = (\frac{7}{2} )

Hence, f(4)  = 7/2  is  TRUE.

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Answer:

C

Step-by-step explanation:

AP Classroom says so

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