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1 year ago

Elisse has 20 meters of ribbon how many 15 cm of ribbon can be cut from it

Mathematics

1 answer:

ASHA 777 [7]1 year ago

8 0

Answer:

133 pieces of 15cm can be cut from the ribbon.

Step-by-Step Explanation:

Length of ribbon = 20 meters

Length needed to be cut = 15 cm

We will convert meters into centimeters.

1 meter = 100 cm

20 meters = 2000 cm

Number of pieces = $\frac{2000}{15}$

Number of pieces = 133.33

Rounding off to nearest whole number = 133

Hence,

133 pieces of 15cm can be cut from the ribbon.

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How many ounces of pure nickel must be added to 150 ounces of alloy 70% pure to make an alloy which is 85% pure?

galben [10]

Answer:

150 oz.

Step-by-step explanation:

There are already 150 ounces of alloy of nickel.

Of this 150 oz, 70% is pure i.e. nickel content = 150(0.7) = 105 oz

Now available is

Nickel Other metals

105 45

Let x oz of pure nickel is added.

Then new alloy will have 105+x oz nickel in total of 150+x oz.

Percentage pure = $\frac{105+x}{150+x} =85%$

Simplify to get

$\frac{105+x}{150+x} =\frac{85}{100} \\\\Cross multiply:\\85(150+x) =100(105+x)\\12750+85x =10500+100x\\100x-85x = 12750-10500\\15x = 2250\\x = 150$

Hence answer is 150 oz should be added.

6 0

1 year ago

Zayed is helping his classmates get ready for their math test by making them identical packages of pencils and calculators. He h

oee [108]

So 72 pencils and 24 calculators
so greates number of identical calculators

this means
what is the biggest number that we can divide 72 and 24 by and get a whole number
this is called the GCM or greatest common multipule

to find the GCM, you factor 72 and group the like ones
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
so the common group is 2 times 2 times 2 times 3 or 24
so the greates number of packs is 24

so pencils
72 divided by 24=72/24=3
3 pencils per pack

24 divided by 24=24/24=1
1 calulator per pack

answer is 3 pencils and 1 calculator per pack

6 0

1 year ago

Read 2 more answers

Select all the pairs that could be reasonable approximations for the diameter and circumference of a cirlce 5 meters and 22 mete

bazaltina [42]

Answer:

Option a) circle 5 meters and 22 meters

Step-by-step explanation:

We are given the following information in the question:

A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.

a) circle 5 meters and 22 meters

$\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}$