The Venn Diagram that represents the problem is shown below
P(E|F) and P(F|E) are the conditional probability.
P(E|F) is given by P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is given by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1
Answer:
99.87% of the store’s total delivery orders will be delivered to consumers with charge
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If a pizza store’s policy is, "Orders delivered within one hour or they’re free!", what percentage of the store’s total delivery orders will be delivered to consumers with charge?
Within one hour, which is 60 minutes. So this is the pvalue of Z when X = 60.



has a pvalue of 0.9987
99.87% of the store’s total delivery orders will be delivered to consumers with charge
First add 2 to both sides, next add 2 + 3 to get 5, next break down the equation into two problems which would be 2x - 5 = 5 and -(2x - 5) = 5, NOT 2x - 5 = -5, so this is the FIRST incorrect step, while step 4 is incorrect because its suppose to be 2x = 5 not 10, that's the second step, not first so answer is:
Answer: A) Step 3.
I see the solution in three steps.
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS<span>≅RS | Reflexive Property
3.) </span><span>△RST ≅ △RSQ | AAS Triangle Congruence Property</span>