Help pleaseeeeeeeeeeeeee

Jayden and Caden share a reward of 140 in a ratio of 2: 5. What fraction of the total reward does Jaden get?

zysi [14]

Jaden gets 40, Caden gets 100

5 0

2 years ago

A bridge is rated to a capacity of 100 British tons. What is the maximum weight the bridge can support in kilograms? (Round to t

S_A_V [24]

Maximum weight the bridge can support in kilograms is 101696

Step-by-step explanation:

Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.

1 British ton = 2240 pounds

1 pound = 0.454 kg

⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg

Step 2: Find how many kilograms are in 100 British tons.

⇒ 100 × 1016.96 = 101696

3 0

2 years ago

N 2004, the General Social Survey (which uses a method similar to simple random sampling) asked, "Do you consider yourself athle

zmey [24]

Answer-

The standard error of the confidence interval is 0.63%

Solution-

Given,

n = 2373 (sample size)

x = 255 (number of people who bought)

The mean of the sample M will be,

$M=\frac{x}{n} =\frac{255}{2373} =0.1075$

Then the standard error SE will be,

$SE=\sqrt{\frac{M\times (1-M)}{n}}$

$SE=\sqrt{\frac{0.1075\times (1-0.1075)}{2373}}=\sqrt{\frac{0.0959}{2373}}=0.0063=0.63\%$

Therefore, the standard error of the confidence interval is 0.63%

6 0

2 years ago

Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well

laiz [17]

Answer:

The value is $P(A) = 0.133617$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 7.5$

The standard deviation is $\sigma = 0.2$

The safest water level is between 7.2 and 7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

$P(A) = 1 - P(7.2 \le X \le 7.8 )$

Here

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } < \frac{X - \mu }{ \sigma }$

Generally $\frac{X - \mu }{ \sigma } = Z (The \ standardized \ value \ of X )$

So

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z$

$P(7.2 < X < 7.8 ) = P(-1.5 < Z$

=> $P(7.2 < X < 7.8 ) = P(Z < 1.5) - P( Z < - 1.5)$

From the z-table the probability of (Z < -1.5) and ( Z <1.5) are

$P(Z < 1.5) = 0.93319$

and

$P(Z < -1.5) = 0.066807$

So

$P(7.2 < X < 7.8 ) =0.93319 - 0.066807$

$P(7.2 < X < 7.8 ) =0.0866383$

So

$P(A) = 1 - 0.0866383$

=> $P(A) = 0.133617$

5 0

2 years ago

Solving for a Confidence Interval: Algebra 2 points possible (graded) In the problems on this page, we will continue building th

baherus [9]

Answer:

Step-by-step explanation:

1) The given inequality is

$|\sqrt{n} \frac{(\bar R_n-p)}{\sqrt{p(1-p)} } |$

$\to n( \bar R _n - p)^2$

$\to n\bar R +np^2-2nR_np$

Arranging the terms with p² and p, we get

$p^2(n+q^2_{\alpha /2)-p(2n \bar R _n+q^2_{\alpha / 2})+n \bar R ^2 _n$

Hence, the inequality is of the form

Ap² + Bp + c < 0

2. A quadratic equation of the form

Ap² + Bp + c < 0 with A > 0 looks like

Check the attached image

The region where the values are negative lies between p₁ and p₂ ...

The p₁ < p < p₂

4 0

2 years ago