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Keith_Richards [23]

1 year ago

11

Napoleon went on a bus trip traveling at a speed of 55 miles per hour for 4 hours which equation will help you find the distance

he traveled

1 answer:

azamat1 year ago

3 0

Answer:

220

Step-by-step explanation:

Easy!

Multiply 55 by 4!

2

55

x 4

--------

220

five times 4 is 20, so put 0 then regroup the 2. Then, 5 times 4 again, but add two!

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At one of New York’s traffic signals, if more than 17 cars are held up at the intersection, a traffic officer will intervene and

Alinara [238K]

Scenarios B, D, and F require a police officer. In scenario B, 1:00-2:00pm, and scenario F, 5:00-6:00pm, there are 24 cars. In scenario D, 3:00-4:00pm, there are 21 cars. Both 24 and 21 are greater than 17, so a traffic officer is needed. However, in other scenarios, the number of cars are all less than 17, and no officer is needed.

8 0

2 years ago

Read 2 more answers

A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year

uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that $p = 0.8$ .

10 students, so $n = 10$

We have to find:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684$

$P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074$

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758$

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that $p = 0.3758$

Two groups, so $n = 2$

We have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691$

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0

2 years ago

Read 2 more answers

Jessica is 5 years older than her sister Jenna. Jenna tells her sister that in 5 years, she will be as old as Jessica was 5 year

Mamont248 [21]

Answer: equations 1,3,4 and 5 stated has solutions.

Step-by-step explanation:

From the question, (x + 5) + 5 = (x + 5) + 5

The equations that represent the situation are:

1. x + 5 = (5 − x) − 5 :which has one solution

2. x + 5 = (x + 5) − 5 : many solutions

3. x + 5 = (x + 5) − 5: no solution

4. x + 5 = (5 − x) − 5 : many solutions

5. (x + 5) + 5 = (x + 5) + 5: many solutions

Equation 2 has no solution. While the other equations have one and more than one solutions.

6 0

2 years ago

Robin and evelyn are playing a target game. the object of the game is to get an object as close to the center as possible. each

svetlana [45]

Here's some of the info

~<span>Evelyn has the greater mean.

~</span>Evelyn’s objects generally landed farther away from the center than Robin’s.<span>
~</span>The object is to get the objects close to the center, so Robin is winning.<span>
</span>

5 0

2 years ago

Read 2 more answers

Suppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. the drive is currently serving a request at cylinder 2,150,

Anni [7]

Answer:

13011, 7586, 7492 , 7424, 9917, and 9137.

Step-by-step explanation:

(1). FCFS is generally based on what is refer to as first come, first serve. That is to say the first one to come will be treated first so, we have that;

FCFS = 81 + 857 + 1084 + 504 + 2256 + 1074 + 1262 + 1167 + 3442 + 1284 = 13011.

(2). (SSTF) Is all about the shortest distance, for example in this question the shortest distance is =

Thus;

Total distance = (2150 - 2069) + (2296 - 2069) + ( 2296 - 2800) +( 3681 - 2800) + (4965 - 3681) + ( 4965 - 1618) + ( 1618-1523) + ( 1523-1212) + ( 1212-544) + ( 544 - 356).

=81 + 227 + 504 + 881 + 1284 + 3347 + 95 + 311 + 668 + 188 = 7586.

(3).SCAN deals with the processing of the nearest request

The distance =146 + 504 +881 + 1284 + 34(4999-4965) + 2930(4999-2069) + 451 + 95 + 311 + 668 +188 = 7492.

(4). LOOK is just like scan.

The distance = 146 + 504 + 881 + 1284 + 2896 + 451 + 95 + 311 + 668 + 188 = 7424.

(5). C-SCAN: this is the kind of scan from one end to the other.

The distance = 146 + 504 +881 +1284 + 34 (4999 - 4965) + 4999 (4999 -0 )+ 356 (356 -0 )+ 188 + 668 + 311 + 95 + 451 = 9917.

(6). C-LOOK : moves in the following order: 2150, 2296, 2800, 3681, 4965, here head moves back 356, 544, 1212, 1523, 1618, 2069.

Thus;

The distance = 146 + 504 + 881+ 1284 + 4609 (4965 - 356) + 188 + 668 + 311+ 95 + 451 = 9137.

4 0

2 years ago