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SVETLANKA909090 [29]
2 years ago
9

Peter babysits his sister on Monday and Friday. He babysits for his neighbor 40% of the days Monday through Friday. He babysits

for his sister and his neighbor on different days. On the weekend, Peter babysits 50% of the days. How many days does Peter babysit each week?

Mathematics
2 answers:
rjkz [21]2 years ago
8 0

Answer:

3 days of the week.

Step-by-step explanation:

Well they removed my answer even though it was correct.

Monday - Friday = 5 days. If you divided 40 by 100 you get .40 which is forty percent in decimal form. 5 * .40 = 2 days.

Weekend is 2 days. If you divide 50 by 100 you .50 which is fifty percent in decimal form. 2 * .50 = 1 day.

Thus he babysat on 3 days of the week.

ExtremeBDS [4]2 years ago
4 0
It’s was right 3 days
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Alice is riding a Ferris wheel, where t is time in seconds. Suppose the Ferris wheel is 22 m tall. Let h(t) = 11cos(12t) represe
Soloha48 [4]

Answer:

Alice reaches 11 metres below the centre as lowest height.

Step-by-step explanation:

Cosine is a bounded function between -1 and 1, so that the lowest height that Alice achieves in Ferris wheel is:

h(t) = 11\cdot \cos (12\cdot t)

Where:

t - Time, measured in seconds.

h(t) - Height with respect to centre, measured in metres.

If \cos (12\cdot t) = -1, then:

h_{min} = 11\cdot (-1)

h_{min} = -11\,m

Alice reaches 11 metres below the centre as lowest height.

7 0
2 years ago
If Serena selects 4 samples from the table, which row
prisoha [69]

Answer:1: Row 3

2: Row 2

3:6 and 10

Step-by-step explanation:

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8 0
2 years ago
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Part A: During what interval(s) of the domain is the water balloon's height increasing?
Advocard [28]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A: During what interval(s) of the domain is the water balloon's height increasing?

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet

Part B: During what interval(s) of the domain is the water balloon's height staying the same?

Between 2 and 4 seconds, the height remains the same at 75 feet. Also from 10 seconds the height of the balloon is at 0 feet

Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest?

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet (i.e. -17.5 ft/s)

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet (i.e. -10 ft/s)

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet (i.e. -10 ft/s)

Hence it decreases fastest from 4 to 6 seconds

Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds

From 10 seconds, the balloon is at the ground, so it remains at the ground (0 feet) even at 16 seconds

6 0
2 years ago
PLEASE HELP!! Which steps can be used to solve 6/7x+1/2=7/8 for x? Check all that apply. A. Divide both sides of the equation by
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Answer:

B. first step

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c. second step

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Step-by-step explanation:

5 0
2 years ago
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A thumbtack that is tossed can land point up or point down. The probability of a tack landing point up is 0.2. A simulation was
sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

This is a binomial probability distribution problem.

Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;

P(X ≥ 2) = P(2) + P(3) + P(4) + P(5)

From the histogram;

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Thus;

P(X ≥ 2) = 0.19 + 0.05 + 0.02 + 0.02

P(X ≥ 2) = 0.28

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