When sodium reacts with chlorine, sodium chloride is produced. Andrew represented this reaction with this equation: Na + Cl2 → 2
2 answers:
Answer:
The correct representation of reaction will be:
Explanation:
Reaction represented by Andrew is not correct as it is not a chemical reaction balanced. Whenever a chemical reaction takes place mass of the reactants always remains conserved as a per as law of conservation of mass.
The law states that mass can neither be created nor be destroyed. And in a balanced chemical reaction number total mass of reactants is always equal to the total mass of products.
The correct representation of reaction will be:
Number of sodium atoms and chlorine atoms on the both sides are equal
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Answer : The pressure in the flask after reaction complete is, 2.4 atm
Explanation :
To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.
where,
P = final pressure in the flask = ?
R = gas constant = 0.0821 L.atm/mol.K
T = temperature =
V = volume = 4.0 L
= moles of
= 0.20 mol
= moles of
= 0.20 mol
Now put all the given values in the above expression, we get:
Thus, the pressure in the flask after reaction complete is, 2.4 atm
According to law of conservation of mass, mass can neither be destroyed nor created in a chemical reaction. Thus, sum of masses of reactants must be equal to sum of masses of products in a reaction.
The chemical reaction is as follows:
Here, sum of masses of Cu and oxygen gas should be equal to CuO formed.
Thus, mass of oxygen will be:
This can be further proved as follows:
The balanced chemical reaction is as follows:
Here, 2 moles of Cu completely reacts with 1 mole of to give 2 moles of
.
Thus, 1 mole of Cu reacts with 0.5 moles of .
The mass of Cu is 508.4 and molar mass is 63.546 g/mol, number of moles can be calculated as follows:
Thus, number of moles of reacting will be:
Molar mass of oxygen molecule is 32 g/mol thus, mass can be calculated as follows:
m=n×M=4 mol×32 g/mol=128 g/mol
This satisfies the law of conservation of mass.