Answer:
(A) 0.15625
(B) 0.1875
(C) Can't be computed
Step-by-step explanation:
We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let X = Amount of time taken by student to complete a statistics quiz
So, X ~ U(32 , 64)
The PDF of uniform distribution is given by;
f(X) = 
, a < X < b where a = 32 and b = 64
The CDF of Uniform distribution is P(X <= x) = 
(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 - = 1 - 
= 
= 0.15625
(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) = 
= 
= 0.34375
P(X < 37) = 
= 
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) Probability that student complete the quiz in exactly 44.74 minutes
= P(X = 44.74)
The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.
Answer:
A = 250(1 + 0.016)^0.75.
Step-by-step explanation:
9 months = 0.75 years
So A = 250(1 + 0.016)^0.75.
Felecia's husband will catch up to her 1 hour 30 minutes after leaving.
Step-by-step explanation:
Step 1; Felecia is traveling at 45 mph, her husband starts 20 minutes after her but travels at a speed of 55 mph. So first we need to calculate how much of a head start Felecia got.
Head start = 
× 45 miles an hour = 15 miles.
So Felecia got a head start of 15 miles.
Step 2; Since Felecia and her husband are traveling at different rates, we can determine how much distance there is between them. Since Felecia is traveling at 45 mph and her husband is traveling at 55 mph, their gap in between is closing at a rate of 55 - 45 = 10 miles every hour. So for every hour, the gap between them is closing by 10 miles.
Total gap initially = 15 miles.
The rate at which gap is being closed = 10 miles an hour.
Time to close the gap = 15 / 10 = 1.5 hours.
Step-by-step explanation:
Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.
Answer:
all prime numbers less than its square root.
Step-by-step explanation:
