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Given Information
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Total number of people = 165
Adult = $6
Child = $2
Total collected = $618
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Assumptions
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Let x be the number of adults and y be the number of children
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Form equations
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Total number of people
x + y = 165
Total amount collected
6x + 2y = 618
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Ans: The two equations are x + y = 165 and 6x + 2y = 618
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The question is not asking for it but if you need to solve the equation to find the answer to x and y
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Present the two equations and solve for x and y
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x + y = 165 ------------------------- (eqn 1)
6x + 2y = 618 ------------------------- (eqn 2)
(eqn 1) :
x + y = 165
x = 165 - y ------------------------- substitute into (eqn 2)
6(165 - y) + 2y = 618
990 - 6y + 2y = 618
4y = 990 - 618
4y = 372
y = 93 ------------------------- substitute into (eqn 1)
x + y = 165
x + 93 = 165
x = 165 - 93
x = 72
x = 72 and y = 93
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Ans: 72 adults and 93 children
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Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:
The amount of deer that were initally in the reserve corresponds to the value of N when t=0
A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
(-5.5,0)
Step-by-step explanation:
The question is on finding the focus point of a parabola
Given y²= 2(x+6).....................................(a)
Compare equation (a) with the standard equation (y-b)²= 2p(x-a)
y²= 2(x+6)------can be written as (y-0)²=2(x+6)
(y-0)²=2(x+6)
(y-b)²= 2p(x-a)
2p=2-----------------divide both sides by 2 to get p
p=2/2=1
For the vertex (a,b)⇒(-6,0)
For the focus point ( a+p/2, b)........................................(b)
Substitute values i equation (b) above
(-6+1/2 ,0) =(-5.5, 0)
Answer:
The mass of 150 books = 41.7kg
The number of books that have mass 20kg = 72 books
Step-by-step explanation:
(I) Number of identical books = 108
Mass of books = 30 kg
Mass of 150 books = ?
Let the mass of 150 books = x kg
To find the mass of 150 books we will use ratio and proportion:
108 books: 30kg = 150 books: x kg
You can also write it like this because ratio can be written in division:
108/30 = 150/x
By cross multiplication:
108x = 150*30
108 x= 4500
Divide both sides by 108
108 x/108 = 4500/108
x= 41.7
Thus the mass of 150 books = 41.7kg
( ii ) The number of books that have a mass of 20 kg = ?
Let assume that the number of books of mass 20 kg = y books
We will again use ratio and proportion method.
108 books: 30kg = y: 20kg
We can write it as:
108/30 = y/20
By cross multiplication:
108 *20 = 30y
2160= 30y
Divide both the terms by 30
2160/30 = 30y/30
72 = y
Therefore the number of books that have mass 20kg = 72 books ....
