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Tems11 [23]
2 years ago
6

Each gallon of paint covers $200$ square feet. I have to paint one side of a wall that is $12$ meters tall and $80$ meters long.

If a foot is approximately $0.3048$ meters, then what is the smallest whole number of gallons I can buy and have enough paint to cover the whole wall?
Mathematics
2 answers:
STatiana [176]2 years ago
6 0
5 gallons of paint would be the least amount of paint you would need
dsp732 years ago
5 0

Answer:

make those cheeks go in circuler motion

Step-by-step explanation:

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Each time Kristine gets paid, she spends $20 and saves the rest. If the amount Kristine earns is represented by x and the amount
faust18 [17]

We are given that Kristine spends $20 and saves the rest each time she get paid.

We can use slope-intercept form y=mx+b to represent the equation.

Where x represents the amount Kristine earns and y represents the amount she saves.

Kristine spends $20. Therefore b= -20.

Plugging mx as just x and b=-20.

<h3>y = x-20.</h3><h3>If we plug y=0, we get </h3><h3>0 = x-20</h3><h3>x=20.</h3><h3>We can see in 4th option we have x-intercept =20.</h3><h3>Therefore, correct option is 4th option. </h3><h3 />

4 0
2 years ago
Read 2 more answers
Given: Circle M with inscribed Angle K J L and congruent radii JM and ML Prove: mAngle M J L = One-half (measure of arc K L) Cir
Luda [366]

Answer:

We need to demontrate

m \angle MJL = \frac{1}{2}arc(KL)

As you can see in the figure below, angle MJL is an inscribed angle for Circle M, that means we can use the inscribed angle theorem to demonstrate the proposition above.

<h3>Therorem.</h3>

<em>The angle formed by two intersecting chords with vertex on the circumference is equal to one-half of the intercepted arc.</em>

<em />

Notice that the theorem says a chord. However, a diameter is a chord by definition, because a chord is a segment that unites to points of the circumference, and a diameter does that too.

Therefore, based on the inscribed angle arc theorem, we have

m \angle MJL = \frac{1}{2}arc(KL)

3 0
1 year ago
Read 2 more answers
The intersection of planes AMR and CMR is<br> a. MR<br> b. AC<br> c. AR<br> d. none of the above
Maurinko [17]
I believe its either a or d

3 0
2 years ago
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Brock is training for a Crossfit competition. He began the training completing pull-ups and box jumps origanally, his training p
siniylev [52]

If the adjusted ratio was 2:7, then

2x is the number of pull-ups

and

7x is the number of box jumps.

You can state that since he completed 63 box jumps at the end of his training, then

7x=63,

x=9

and

2x=18.

The total number of exercises performed is 2x+9x=18+63=81.

As at start the ratio was 5:4, then

5y was the number of pull-ups

and

4y was the number of box jumps.

Therefore, 5y+4y=81,

9y=81,

y=9

and 5y=45, 4y=36.

Answer: Initially: 45 pull-ups and 36 box jumps. At the end: 18 pull-ups and 63 box jumps.

8 0
2 years ago
David is throwing a stone in the air at an angle from the ground with an initial velocity of 30 feet per second. The equation gi
Shtirlitz [24]

Answer:

42 feet.

Step-by-step explanation:

h=-10t² + 40t +2

The vertex of the quadratic function described by the equation is located at

 t = -(40)/(2(-10)) = 2

Next is to find the value of height at t=2 will be

 h = -10(2²) +40(2) +2 = -40 +80 +2 = 42feet

The maximum height is 42 feet.

7 0
2 years ago
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