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Rashid [163]
1 year ago
7

3._____ If you investigated cells from a lab mouse with 40 chromosomes you would find a total of ___ sister chromatids after the

___ stage.
A. 10; G1
B. 40; G2
C. 20; M
D. 80; S
Biology
1 answer:
yulyashka [42]1 year ago
4 0
The answer is 10;G1” Write that
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Calix’s karyotype showed that he has a genotype of XXY. Explain how nondisjunction caused Calix to be XXY.
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A XY or XY gamete fuses with a normal gamete (X or Y)

Explanation:

Meiotic nondisjunction is the phenomenon whereby chromosomes fail to separate during meiosis I or II. Meiotic nondisjunction leads to the formation of abnormal gametes I.e. gametes with additional or missing chromosomal piece.

The fusion of these abnormal gametes produced by nondisijuction with a normal gamete (X or Y chromosome). This leads to a condition called ANEUPLOIDY, which is a chromosomal disorder. In the case od Calix, XXY is an ANEUPLOIDY state that could have resulted because there was a fusion between a XX gamete and Y gamete or XY and X. The XY or XX gametes are produced as a result of nondisijuction.

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