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kap26 [50]
2 years ago
4

The set of life spans of an appliance is normally distributed with a mean mc012-1.jpg = 48 months and a standard deviation mc012

-2.jpg = 8 months. What is the z-score of an appliance that stopped working at 64 months?
Mathematics
2 answers:
FromTheMoon [43]2 years ago
7 0
We are given with
mean = u = 48 months
standard deviation = d= 8 months
The condition is that the appliance with stop working at 64 months = d

The z-score is
z = (x - u) / d
z = (64 - 48) / 8
z = 2<span />
Greeley [361]2 years ago
3 0

Answer:

<em>The z-score of an appliance that stopped working at 64 months is </em><em>2</em>

Step-by-step explanation:

We know that,

Z=\dfrac{X-\mu}{\sigma}

where,

Z = Z score,

X = raw score = 64

μ = mean = 48

σ = standard deviation = 8

Putting the values,

Z=\dfrac{64-48}{8}=\dfrac{16}{8}=2

Therefore, the z-score of an appliance that stopped working at 64 months is 2.

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