Question

What is the quotient when −3x3 + 5x + 14 is divided by x − 2?

Answer 1

Answer:

$-(3x^2+6x+7)$

Step-by-step explanation:

We have been given two expressions and we are asked to find the quotient of our given expressions.

$\frac{-3x^3+5x+14}{x-2}$

First of all we will factor numerator of our rational expression as:

$-(3x^3-5x-14)$

$-(3x^2+6x+7)(x-2)$

$\frac{-(3x^2+6x+7)(x-2)}{x-2}$

Upon cancelling out x-2 from numerator and denominator we will get,

$-(3x^2+6x+7)$

Therefore, the quotient of our division problem is $-(3x^2+6x+7)$.

Answer 2

Answer:  Quotient is $-3x^2-6x-7$

Explanation:

We have been given the two expressions dividend which is $-3x^3+5x+14$  and divisor$x-2$

when we divide the dividend with divisor we select the degree one less than the dividend so that when it gets multiplied by the dividor will give the equal degree which is required to cancel the first term of the dividend.

By Long division method we can do this.