Answer:
Python Code:
def validate_url(url):
#Creating the list of valid protocols and file name extensions
valid_protocols = ['http', 'https', 'ftp']
valid_fileinfo = ['.html', '.csv', '.docx']
#splitting the url into two parts
url_split = url.split('://')
isProtocolValid = False
isFileValid = False
#iterating over the valid protocols and file names for validity
for x in valid_protocols:
if x in url_split[0]:
isProtocolValid = True
break
for x in valid_fileinfo:
if x in url_split[1]:
isFileValid = True
break
#Returning the result if the URL has both valid protocol and file extension
return (isProtocolValid and isFileValid)
url = input("Enter an URL: ")
print(validate_url(url))
Explanation:
The image of the output code is attached. Hope it helps.
Answer:
C++.
Explanation:
<em>Code snippet.</em>
#include <map>
#include <iterator>
cin<<N;
cout<<endl;
/////////////////////////////////////////////////
map<string, string> contacts;
string name, number;
for (int i = 0; i < N; i++) {
cin<<name;
cin<<number;
cout<<endl;
contacts.insert(pair<string, string> (name, number));
}
/////////////////////////////////////////////////////////////////////
map<string, string>::iterator it = contacts.begin();
while (it != contacts.end()) {
name= it->first;
number = it->second;
cout<<word<<" : "<< count<<endl;
it++;
}
/////////////////////////////////////////////////////////////////////////////////////////////////////////
I have used a C++ data structure or collection called Maps for the solution to the question.
Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.
The four levels of organization incorporate official chiefs, program executives, improvement chiefs, and give essayists. The meaning of business organization is a program of study offered at colleges and schools that attention on business hypothesis, practices, and administration. A case of business organization is a class on the standards of bookkeeping.
Answer:
def words_in_both(a, b):
a1 = set(a.lower().split())
b1 = set(b.lower().split())
return a1.intersection(b1)
common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')
print(common_words)
Explanation:
Output:
{'all', 'of', 'jack'}
The organisation that would best aid families and choose the right products to buy would be the American Association of Family and Consumer Sciences. In addition, the institution is primarily composed of home economists wherein these professionals promote efficient consumer consumption of goods.
