Question

PLEASE HELP ME WITH THIS ONE QUESTION

Answer 1

Answer:

D. 56

Step-by-step explanation:

The general solution for the number of combinations with repetition is represented by the following expression:

$x = \frac{(n + r - 1)!}{r!\cdot (n-1)!}$ (1)

Where:

$n$ - Total number of elements.

$r$ - Number of the sample.

If we know that $n = 6$ and $r = 3$, then the number of combinations with repetition:

$x = \frac{(6+3-1)!}{3!\cdot (6-1)!}$

$x = 56$

Hence, correct answer is D.