Answer:
Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.
Big Oh notation is used to describe time complexity, execution time of an algorithm.
Big Oh describes the worst case to describe time complexity.
For the equation; T(N) = 10000*N + 0.00001*N^3.
To calculate first of all discard all th constants.
And therefore; worst case is the O(N^3).
Answer:
A Program was written to carry out some set activities. below is the code program in C++ in the explanation section
Explanation:
Solution
CODE
#include <iostream>
using namespace std;
int main() {
string name; // variables
int number;
cin >> name >> number; // taking user input
while(number != 0)
{
// printing output
cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;
// taking user input again
cin >> name >> number;
}
}
Note: Kindly find an attached copy of the compiled program output to this question.
The question is incomplete:
Darius needs to include contact information in an email that he is sending to a colleague . Which option should he choose from the ribbon?
-Attach File
-Attach Item
-Attach Policy
-Attach Signature
Answer:
-Attach Signature
Explanation:
-Attach file is an option that allows you to include any type of file that you need to send in the email.
-Attach Item is an option that allows you to include an element from your email like a message in your inbox to the current one you are writing.
-Attach Policy is not an option.
-Attach Signature is an option that allows you to include a previously created signature with the contact information at the end of the message.
According to this, the answer is that the option that Darius should choose from the ribbon is attach signature because he needs to include contact information.
Answer:
// program in C++ to check leap year.
// include header
#include<iostream>
using namespace std;
// main function
int main() {
// variable
int inp_year ;
// ask user to enter year
cout<<"Enter year:";
// read year
cin>>inp_year;
// check year is leap or not
if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))
// if leap year , print leap year
cout<<inp_year<<" is a leap year.";
else
// print not leap year
cout<<inp_year<<" is not a leap year.";
return 0;
}
Explanation:
Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not leap year.
Output:
Enter year:1712
1712 is a leap year.
