It is required to dewater a construction site of 80 m by 80 m. The bottom of the construction will be 1.5 m below the initial wa
1 answer:
You might be interested in
Answer:
gauge pressure at stagnation point is 1836.07 pa, the flow will be compressible at 1050 km/h.
Explanation:
The airplane is flying at a velocity of 350 km/hr. Then assume that air is also flowing at a speed of 350 km/hr The point at which velocity of flow of fluid is zero at that point kinetic energy of the fluid is converted into pressure head, that pressure head is called stagnation pressure.
Applying Bernoulli's equation between points (1) and (2), we can get:
=
A both points (1) and (2) are on the same level;
- Velocity of air at point (2),
= 0
from the properties of air table: Density of air at 10500 m is 0.3885
=
[/tex]
At stagnation point, the gauge pressure = 1836.07
If the airplane speed is increased to 1050 km/h(this is about 3 time the initial speed), the flow will be considered compressible because at low speed gases are considered to be incompressible.
Answer:
Hello there, please check step by step explanations to get answers.
Explanation:
Given that:
5-hp single-cylinder engine is used. At most, the belt transmits 60 percent of this power. The driving sheave has a diameter of 6.2 in. and the driven, 12.0 in. The belt selected should be as close to 92 in pitch length as possible. The engine speed is governor-controlled to a maximum of 3100 rev/min. Select a satisfactory belt, and specify it using the standard designation.
See attached documents for clearity and step by step procedure to answer
Answer:
maximum value of the power delivered to the circuit =3.75W
energy delivered to the element = 3750e^{ -IOOOt} - 7000e ^{-2OOOt} -3750
Explanation:
V =75 - 75e-1000t V
l = 50e -IOOOt mA
power = IV = 50 * 10^-3 e -IOOOt * (75 - 75e-1000t)
=50 * 10^-3 e -IOOOt *75 (1 - e-1000t)
=
maximum value of the power delivered to the circuit =3.75W
the total energy delivered to the element =