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aev [14]
2 years ago
3

A sum of money increased by its 0.05 in every 6 months after how long time the annual compound interest on Rs. 4000 will be Rs.

1324?​
Mathematics
1 answer:
Tanya [424]2 years ago
5 0

Answer:

3 x 2 = 6 years to get Rs. 1324

Step-by-step explanation:

This is a mathematical relationship that transcends currencies. In other words, it also applies to Dollars, Pounds and Yen.

“Annual compound interest” is a phrase of dubious meaning. The process is a “compound interest problem”, but the item I think you are looking for is simply the amount of interest.

Month 0: interest: 0 balance: 4,000

Month 6: interest; 200 balance: 4,200

Month 12: interest 210 balance: 4,410 12-month total interest: 410

Month 18: interest: 220.5 balance: 4,630.5 12-month total interest: 430.5

Month 24: interest: 231.525 balance: 4,862.025 12-month total interest: 452.025

Month 30: int: 243.10125 bal: 5,105.12625 12-month total int: 474.35125

Keep expanding this progression until the 12-month total interest meets or exceeds 1324, the answer will be the number of months in the last line.

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2 years ago
Adam is using the equation (x)(x + 2) = 255 to find two consecutive odd integers with a product of 255. When Adam solves the pro
kondaur [170]
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3 0
2 years ago
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The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,
juin [17]

Answer:

The width is: w(x)=4x^2

The length is l(x)=2x^2+3x+5

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

a(x)=8x^5+12x^3+20x^2

The width of the rectangle is the greatest common factor of 8x^5,  12x^3 and 20x^2

That is the width is: w(x)=4x^2

We now divide the area by the width to obtain the length of the rectangle:

l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}

This simplifies to:

l(x)=\frac{8x^5}{4x^2}+\frac{12x^3}{4x^2}+\frac{20x^2}{4x^2}

l(x)=2x^2+3x+5

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For each 12 mm of coloured fabric Sarah uses to make her curtains, she also uses 2 cm of white fabric. Express the amount of whi
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Answer:

3:5 mm

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The resistance of a strain gauge is normally distributed with a mean of 100 ohms and a standard deviation of 0.3 ohms. To meet t
zloy xaker [14]

Answer: 0.6827

Step-by-step explanation:

Given : The resistance of a strain gauge is normally distributed .

Population mean : \mu=100

Standard deviation : \sigma=0.3

Let x be the random variable that represents the resistance of a strain gauge is normally distributed .

z-score : z=\dfrac{x-\mu}{\sigma}

To meet the specification, the resistance must be within the range 100±0.7 ohms i.e. (99.3,100.7).

For x = 100.7

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