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Rus_ich [418]
2 years ago
9

If the nominal rate of interest is 10% per annum and there is quarterly compounding, the effective rate of interest will be: a)

10% per annum b) 10.10 per annum c) 10.25%per annum d) 10.38% per annum​
Mathematics
1 answer:
sdas [7]2 years ago
6 0

9514 1404 393

Answer:

  d) 10.38%

Step-by-step explanation:

The multiplier for four quarters of quarterly compounding is ...

  (1 +10%/4)^4 = 1.025^4 = 1.103812890625

This is about 1 + 10.38%.

The effective rate of interest is about 10.38% per annum.

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Step-by-step explanation:

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Find dy/dx implicitly and find the largest interval of the form −a < y < a or 0 < y < a such that y is a differentia
mylen [45]

Answer:

dy/dx = -1/√(1 - x²)

For 0 < y < π

Step-by-step explanation:

Given the function cos y = x

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-siny dy/dx = 1

dy/dx = -1/siny (equation 1)

But cos²y + sin²y = 1

=> sin²y = 1 - cos²y

=> siny = √(1 - cos²y) (equation 2)

Again, we know that

cosy = x

=> cos²y = x² (equation 3)

Using (equation 3) in (equation 2), we have

siny = √(1 - x²) (equation 4)

Finally, using (equation 4) in (equation 1), we have

dy/dx = -1/√(1 - x²)

The largest interval is when

√(1 - x²) = 0

=> 1 - x² = 0

=> x² = 1

=> x = ±1

So, the interval is

-1 < x < 1

arccos(1) < y < arxcos(-1)

= 0 < y < π

6 0
2 years ago
Enter the expression 2cos2(θ)−1 , where θ is the lowercase Greek letter theta. 2cos2(θ)−1 2 c o s 2 ( θ ) − 1 = nothing
yulyashka [42]

We have to evaluate

=2 cos 2Ф - 1

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 C = cos²Ф - sin²Ф

Possible Answers are

1.

=2 ×(2cos²Ф-1)-1

=4cos²Ф-2-1

=4cos²Ф - 3

2.

=2×(1 -2 sin²Ф)-1

=2- 4sin²Ф-1

=1 - 4sin²Ф

3.

=2× ( cos²Ф - sin²Ф) -1

=2 cos²Ф - 2sin²Ф-1

8 0
2 years ago
State the size of angle OAB, giving a reason for your answer
Alja [10]

Answer:

Angle OAB = 90°

Reason: tangent theorem of a circle

Step-by-step explanation:

The diagram given shows a tangent line of the given circle with center O. The tangent touches the circle at point A.

The diagram also shows the radius of the circle, OA, drawn from the center to the circle to meet at the point of tangency.

Thus, according to the Tangent Theorem of a circle, the point at which the radius drawn from the center meets the point of tangency = 90°. The tangent is perdendicular to the radius drawn to meet at the point of tangency.

Therefore, angle OAB = 90°

5 0
2 years ago
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