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iris [78.8K]
2 years ago
9

Five students want to play dodgeball and they all want to be a team captain. To be fair, the gym coach decides to place the name

s of all five students into a hat, mix well, and select two names at random without replacement. The names chosen will be the team captains. Each outcome in the sample space for the random selection of two team captains is equally likely. What is the probability of each outcome in the sample space?
1/25
1/20
1/10
1/5

WARNING! PEOPLE HAVE BEEN PUTTING THE FOLLOWING WRONG ANSWERS:
1/10 AND 1/5 --> THESE TWO ARE WRONG.

I THINK IT IS 1/20. CAN SOMEONE CONFIRM?
Mathematics
1 answer:
sesenic [268]2 years ago
4 0

Answer:

1/25

Step-by-step explanation:

There are five students. They all have a 1/5 chance. You have to include the chance of all five students, so each student has a 1/25 chance.

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Describe in words the region of double-struck R3 represented by the inequality. 0 ≤ z ≤ 7 The inequality 0 ≤ z ≤ 7 represents al
qwelly [4]

Answer:

All points between z = 0 and z = 7 along the z-azis in R3 x-y-z plane

Step-by-step explanation:

The inequality 1 \le z  \le7 represents all sets of points on the z-axis in the R3 plane that lies bewteen z = 0 and z= 7.

It is represents a line segment joining two point z= 0 and z=7 along z- axis in the R3 plane, while x=0 and y=0 on the x-y plane.

4 0
2 years ago
Given f(x) = 70 + 11x, find x when f(x) =158
Mumz [18]

Answer:

\huge  \boxed{x = 8}

Step-by-step explanation:

f(x) = 70 + 11x

To find the value of x when f(x) =158 , equate f(x) to 158

We have

70 + 11x = 158 \\ 11x = 158 - 70 \\ 11x = 88

Divide both sides by 11

\frac{11x}{11}  =  \frac{88}{11}  \\

We have the final answer as

<h3>x = 8</h3>

Hope this helps you

5 0
2 years ago
4. Given directed line segment CD, if point E divides CD three-fourths of the way from C to D, find the coordinates of E, then p
cricket20 [7]

Answer:

Point E is given by \left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )

Step-by-step explanation:

Let points C and D be (x_0,y_0),\,(x_1,y_1) and let point E divides it in ratio m:n.

Then coordinates of point E are given by \left ( \frac{mx_1+nx_0}{m+n},\frac{my_1+ny_0}{m+n} \right )

Put m:n=3:4

Point E is given by \left ( \frac{3mx_1+4x_0}{3+4},\frac{3y_1+4y_0}{3+4} \right )=\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )

Now plot point E.

Download pptx
3 0
2 years ago
A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram
azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The standard deviation of sample mean is inversely proportional to the sample size, <em>n</em>.

So, if <em>n</em> increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of <em>n</em> from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for <em>n</em> = 64 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7

The standard deviation of the sample mean for <em>n</em> = 196 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4

The standard deviation of the sample mean decreased from 0.7 to 0.4 when <em>n</em> is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of <em>n</em> from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for <em>n</em> = 784 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2

The standard deviation of the sample mean for <em>n</em> = 49 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8

The standard deviation of the sample mean increased from 0.2 to 0.8 when <em>n</em> is decreased from 784 to 49.

Hence, the variance also increases.

6 0
2 years ago
In the diagram, AB and EF are horizontal lines and CB is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates o
sergij07 [2.7K]
For the answer to the question above, are your diagram shows that the horizontal lines and is a vertical line segment where as FB: 3 , If C is equaled to 3, so the coordinate of the point D would be (-6,-4).I hope my answer helped you.
8 0
2 years ago
Read 2 more answers
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