I am going to assume that "v" is meant to be a "y"
the answer is b. (3)/(5x^6 y^6)
Answer:
124.67cm³
Step-by-step explanation:
==>Given:
Dimensions of current can:
Height (h) = 12cm
Diameter = 6cm (radius = 3cm)
Volume of current can (V1) = 339.12 cm³
Dimensions of future cans to be increased multiple of 1.11:
height = 12cm × 1.11 = 13.32 cm
radius = 3cm × 1.11 = 3.33 cm
Volume of future can (V2) = πr²h = 3.14*3.33²*13.32
= 3.14*11.0889*13.32 = 463.791025
V2 ≈ 463.79 cm³
==>Find how much more would new cans hold = Volume of new can - volume of current can
= 463.79 cm³ - 339.12 cm³
= 124.67cm³
Answer:
A
Step-by-step explanation:
Just took the quiz on edgenuity
Answer:
Step-by-step explanation:
The key to solving this question is to find the distance bwtween the two points given
distance=y2-y1/x2-x1
(2,4)(4,8)
2=x1,4=y1
4=x2
8=y2
8-4/4-2
4/2=2
The depth of the water is increasing by 2 ft each minute
