Answer:
C3H8 + 5O2 ====> 3CO2 + 4H20
Answer:
(C) bent 109
(2) 
Explanation:
The number of bond pairs = 2
Number of lone pairs = 2
The general formula is - 
According to VSEPR theory, the atoms will form a geometry in such a way that there is minimum repulsion and maximum stability.
The central atom has 2 bond pairs and 2 lone pairs. Hybridization is sp³. The geometry is bent shape which has an angle of approximately 105.5°. It original has angle of 109.5° but due to lone pair repulsion, it reduces.
Answer - (C) bent 109
Square pyramidal possibility:- (2) 
The central atom has 5 bond pairs and 1 lone pair. Hybridization is sp³d. The geometry is square pyramidal in which the equatorial bonds has an angle of 120° and axial bond has an angle of 90°.
Answer:
78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene
Explanation:

Moles of propene = 
According to reaction, 1 mole of propene gives 1 mole of propane.
Then 0.6538 moles of bromo-propane will give:

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene.
Answer: Option (c) is the correct answer.
Explanation:
When there will be interaction between 2,3-bisphosphoglycerate (BPG) and Lys residue in the central cavity of hemoglobin then it will change into Ser residue. After that, the it will lead to less stable formation of deoxygenated state (T state).
Since, serine is not a charged amino acid therefore, it will lead to a decrease in the binding affinity of hemoglobin for 2,3-bisphosphoglycerate.
As a result, stability of the T state will decrease.
Thus, we can conclude that in the given situation the T state would be less stable.
Answer:
46.6 laps
Explanation:
Step 1: Given data
- Length of the lap (l): 1056 ft
- Total distance to be run (d): 15.0 km
Step 2: Convert "l" to km
We will use the conversion factor 1 km = 3280.84 ft.
1056 ft × (1 km / 3280.84 ft) = 0.3219 km
Step 3: Calculate the number of laps that you should run
We will use the following expression.
laps = d/l
laps = 15.0 km/(0.3219 km/lap)
laps = 46.6 laps