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sammy [17]
2 years ago
15

What is the concentration in molarity of an aqueous solution which contains 18.41% by mass acetonitrile (MM = 41.05 g/mol)? The

density of the solution is 0.8100 g/mL.
Chemistry
1 answer:
Ronch [10]2 years ago
5 0

Answer:

which contains 5.21% by mass ethylene glycol (mm=62.07g/mol)? The density of the solution is 1.04g/ml.

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When C3H8 burns completely inn excess of oxygen, the products formed are
kolezko [41]

Answer:

C3H8 + 5O2 ====> 3CO2 + 4H20

4 0
2 years ago
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct
sashaice [31]

Answer:

(C) bent 109

(2) XY_5Z

Explanation:

The number of bond pairs = 2

Number of lone pairs = 2

The general formula is - XY_2Z_2

According to VSEPR theory, the atoms will form a geometry in such a way that there is minimum repulsion and maximum stability.  

The central atom has 2 bond pairs and 2 lone pairs. Hybridization is sp³. The geometry is bent shape which has an angle of approximately 105.5°. It original has angle of 109.5° but due to lone pair repulsion, it reduces.

Answer - (C) bent 109

Square pyramidal possibility:- (2) XY_5Z

The central atom has 5 bond pairs and 1 lone pair. Hybridization is sp³d. The geometry is square pyramidal in which the equatorial bonds has an angle of 120° and axial bond has an angle of 90°.

5 0
2 years ago
What mass of 2-bromopropane could be prepared from 25.5 g of propene? Assume a 100% yield of product.
Mamont248 [21]

Answer:

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene

Explanation:

C_3H_6+HBr\rightarrow C_3H_7Br

Moles of propene = \frac{25.5 g}{39 g/mol}=0.6538 mol

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

0.6538 mol\times 120 g/mol=78.46 g

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene.

5 0
2 years ago
If a Lys residue that interacts with 2,3-bisphosphoglycerate (BPG) in the central cavity of hemoglobin is changed to a Ser resid
masha68 [24]

Answer: Option (c) is the correct answer.

Explanation:

When there will be interaction between 2,3-bisphosphoglycerate (BPG) and Lys residue in the central cavity of hemoglobin then it will change into Ser residue. After that, the it will lead to less stable formation of deoxygenated state (T state).

Since, serine is not a charged amino acid therefore, it will lead to a decrease in the binding affinity of hemoglobin for 2,3-bisphosphoglycerate.

As a result, stability of the T state will decrease.

Thus, we can conclude that in the given situation the T state would be less stable.

3 0
2 years ago
A running track measures 1056 ft per lap. To run 15.0 km, how many laps should you run?
Neporo4naja [7]

Answer:

46.6 laps

Explanation:

Step 1: Given data

  • Length of the lap (l): 1056 ft
  • Total distance to be run (d): 15.0 km

Step 2: Convert "l" to km

We will use the conversion factor 1 km = 3280.84 ft.

1056 ft × (1 km / 3280.84 ft) = 0.3219 km

Step 3: Calculate the number of laps that you should run

We will use the following expression.

laps = d/l

laps = 15.0 km/(0.3219 km/lap)

laps = 46.6 laps

7 0
2 years ago
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