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1 year ago

Find the value of 200/33 up to one place decimal.

Mathematics

1 answer:

Sergio [31]1 year ago

7 0

Answer:

6.1

Step-by-step explanation:

6.06060606061

and you round up making it 6.1

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Calvin throws 12 sheets of paper up in the air and randomly catches one of the sheets as they float down. Of the 12 sheets of pa

Leokris [45]

Total number of sheets are 12.

Total number of white sheets= 9

Total number of red sheets = 3

Probability = Number of favorable outcomes/ total number of outcomes.

Hence

When Calvin throws the sheets in the air, the probability that he gets a white sheet is

$\frac{9}{12}$

which equals to $\frac{3}{4}$

that becomes 0.75

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2 years ago

Each box of Fred’s Fudge is constructed from 2 triangles and 3 rectangles. What is the shape of each box?

Delvig [45]

The answer is a rectangular prism

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1 year ago

Supervisor: "I am giving you 10 business days to make a 4% improvement on your average quality score. Your current average quali

kobusy [5.1K]

"Then I will need an average quality score of <u>3.28</u> to meet 85.28 goal."

<u>Step-by-step explanation</u>:

current average quality score = 82
improvement on average quality score = 4% of 82

⇒ (4/100) $\times$ 82

⇒ 82/25

⇒ 3.28

The improved average quality score = 82+3.28 = 85.28

The employee needs an average quality score of 3.28 to meet the goal of 85.28

5 0

1 year ago

A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall

avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

$P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625$

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

$P(A \cap B) = 0.125\frac{1}{7} = 0.0179$

What is the probability that today is Monday?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286$

0.0286 = 2.86% probability that today is Monday.

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1 year ago

Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1

irina [24]

$\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}$

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0

1 year ago

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Find the value of 200/33 up to one place decimal.​

Find the value of 200/33 up to one place decimal.