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nataly862011 [7]
2 years ago
12

Set of negative integers greater than -6. Write the given sets in roster form.

Mathematics
1 answer:
LiRa [457]2 years ago
7 0

I don't know what rosters form is but the integers are -5, -4, -3, -2, and -1.

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Make x the subject of the formula 6x+a=5(x+t)
Mademuasel [1]
1. Expand
6x + a = 5x + 5t
2. Get x on one side
6x - 5x = 5t - a
3. Simplify
x = 5t - a (I think)
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2 years ago
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Find the length of the segment indicated. Round your answer to the nearest tenth if necessary.
Elena-2011 [213]

<u>Given</u>:

The length of the segment of the chord DB is 8.2 units.

The length of the segment AB is 6.9 units.

The length of the radius AC be x units.

We need to determine the value of x.

<u>Length of BC:</u>

Since, we know the property that, "if a radius is perpendicular to the chord, then it bisects the chord".

Thus, applying the above property, we have;

DB ≅ BC

8.2 = BC

Thus, the length of BC is 8.2 units.

<u>Value of x:</u>

Since, ∠B makes 90°, let us apply the Pythagorean theorem to determine the value of x.

Thus, we have;

AC^2=AB^2+BC^2

Substituting the values, we have;

x^2=6.9^2+8.2^2

x^2=47.61+67.24

x^{2} =114.85

x=10.7

Thus, the value of x is 10.7 units.

Hence, Option A is the correct answer.

4 0
2 years ago
John drove from station A to station B a distance of 224 miles. On his way back, he increased his speed by 10 mph. If the journe
meriva

Answer: 70 mph

Step-by-step explanation:

224/x =224/x+10 +24/60

Solve equation

5 0
2 years ago
HELP FAST PLEASE
kramer

Answer:

y = 14

Step-by-step explanation:

proportional relation: y = kx

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2 years ago
The number of home runs scored by a certain team in one baseball game is a random variable with the distribution x 0 1 2 P(x) 0.
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Answer: E(Y) = 1.6 and Var(Y)=1.12

Step-by-step explanation:

Since we have given that

X       0        1       2

P(X)   0.4   0.4    0.2

Here, number of games = 2

So, Y=X_1+X_2

Since X_1\ and\ X_2 are independent variables.

so, E[Y]=2E[X]\\\\Var[Y]=2Var[X]

So, we get that

E(X)=0.4\times 0+0.4\times 1+0.2\times 2=0.8\\\\and Var[x]=E[x^2]-(E[x])^2\\\\E[x^2]=0\times 0.4+1\times 0.4+4\times 0.2=1.2\\\\So, Var[x]=1.2-(0.8)^2\\\\Var[x]=1.2-0.64=0.56

So, E[y]=2×0.8=1.6

and Var[y]=2×0.56=1.12

Hence, E(Y) = 1.6 and Var(Y)=1.12

5 0
2 years ago
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