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lys-0071 [83]
2 years ago
9

Mike and Kim invest $18,000 in equipment to print yearbooks for schools. Each yearbook costs $5 to print and sells for $30. How

many yearbooks must they sell before their business breaks even?
Mathematics
2 answers:
Airida [17]2 years ago
7 0

Answer:

They must sell 720 books.

Step-by-step explanation:

Let x be the number of year books that they must sell before their business breaks even.

Given,

The cost price of each year book = $ 5  

The cost price of x books = 5x dollars,

Also, the investment = $ 18000,

Thus, the total cost of the x books = ( 5x + 18000 ) dollars

Now, the selling price of the book = $ 30,

So, the total revenue = The total selling price of x books = 30x

In the case of break even,

Total revenue = Total cost

⇒  30x = 5x + 18000

Subtracting 5x on both sides,

30x - 5x = 18000

⇒ 25x = 18000

Divide both sides by 25,

x =  720

Hence, they must sell 720 yearly books before their business breaks even.

vampirchik [111]2 years ago
4 0
This is a simple equation since they get 30$ and it costs  5$ that means they make 25$ each yearbook. Then you divide 18,000 by 25 and get 720

They have to sell 720 yearbooks :) hope this helped
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a shopkeeper sold goods for rs 2400 and made a profit of 25% in the process. find his profit per cent if he had sold his goods f
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case 1,

Let the CP be ₹x,

SP = ₹2400

Profit = SP – CP

= 2400 – x

Profit % = {(2400–x)/ x} × 100%

According to the question,

{(2400–x)/ x} × 100 = 25

=> (2400–x)/ x= 25 /100

=> 100(2400–x) = 25x [ cross multiplication]

=> 240000 – 100x = 25x

=> 240000 = 25x + 100x

=> 240000 = 125x

=> 240000/125 = x

=> x = 1920

So, CP = ₹1920

case 2,

SP = ₹2040

Profit = SP – CP

= 2040 – 1920

= ₹120

profit % = 120/1920 × 100%

= 16%

<h3>Thus, his profit would be 16% if he had sold his goods for ₹2040.</h3>
6 0
2 years ago
Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:
svp [43]

Answer:

Option B. w=5h-8

Step-by-step explanation:

we have

h=(\frac{1}{5})w+(\frac{8}{5})

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

5h=w+8

subtract 8 both sides

5h-8=w+8-8

5h-8=w

Rewrite

w=5h-8

4 0
2 years ago
You have found a home that you are interested in purchasing. Instead of a conventional loan, you agree to pay the premium for th
Elena-2011 [213]
Hi there
Down payment is 5% of the amount listed
100-95=5%
So the amount of down payment is
95,278×0.05=4,763.9

Hope it helps
5 0
2 years ago
please solve this problem : 9 boys take part in a relay event each boy runs 3/5 of a mile how far do the boys run please help
Artist 52 [7]
All you need to do is multiply the amount of boys by the distance each boy runs.

9x3/5=5.4 miles

The boys run a combined distance of 5.4 miles.
7 0
2 years ago
The price of a train ticket consists of an initial fee plus a constant fee per stop.
murzikaleks [220]

Answer:

Initial Fee is $2.

Step-by-step explanation:

Given:

Stops  Price (dollars)

3         6.50

7         12.50

11         18.50

Also Given:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

So let the Cost of initial fee be 'x'.

Also Let the Cost of Constant fee be 'y'.

Now Equation can framed as;

Price (P) = x + (y\times \textrm{Number of Stops})

Now According to table;

Number of stops = 3

Price = 6.50

So equation can be framed as;

x+3y =6.50 \ \ \ \ equation \ 1

Also According to table;

Number of stops = 7

Price = 12.50

So equation can be framed as;

x+7y =12.50 \ \ \ \ equation \ 2

Now Subtracting equation 1 from equation 2 we get;

(x+7y)-(x+3y) =12.50-6.50\\\\x+7y-x-3y=6\\\\4y =6\\\\y= \frac{6}{4}=\$1.5

Substituting the value of y in equation 1 we get;

x+3\times1.5=6.50\\\\x+4.5=6.50\\\\x =6.50-4.5 = \$2

Hence Initial Fee is $2.

8 0
2 years ago
Read 2 more answers
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